Angular 2 different components with same route

谁说我不能喝 提交于 2019-12-17 14:47:00

问题


I have an application, which need to separate authenticated and guest users components. But I need, that both components will be loaded by '/' route. I wrote

{
    path: 'desktop',
    loadChildren: 'app/member/member.module#MemberModule',
    canActivate: [LoggedInGuard],
},
{
    path: '',
    loadChildren: 'app/guest/guest.module#GuestModule',
    canActivate: [GuestGuard],
},

And it works. But how to make, that both component load by same url? I had tried to write path: '' for Member's module route, but the second router rule is not performed. Here are guards code:

LoggedInGuard:

canActivate(route: ActivatedRouteSnapshot, state: RouterStateSnapshot): boolean {
    if(this.sessionService.isLoggedIn()) {
        return true;
    } else {
        return false;
    }
}

GuestGuard:

canActivate(route: ActivatedRouteSnapshot, state: RouterStateSnapshot): boolean {
    if(!this.sessionService.isLoggedIn()) {
        return true;
    } else {
        return false;
    }
}

Here is a plunker: http://embed.plnkr.co/VaiibEVGE79QU8toWSg6/

How should I do it properly? Thank you


回答1:


So i was finally able to do this. The thing is Angular uses first match policy, so we need to match routes in a guard-type way, to be sure that right route with right module will be matched.

First thing we need to add custom matchers for our routes which will only match them on conditions that we want (user type for example).

{
 path: 'samePath',
 matcher: firstMatcher,
 loadChildren: '../first/first.module#FirstModule'
},
{
 path: 'samePath',
 matcher: secondMatcher,
 loadChildren: '../second/second.module#SecondModule'
}

And matchers code is something like this: In here i injected AuthService service from AppModule, and checked users type with it. So routes can be matched according to users type.

import { applicationInjector } from '../../main';

export function firstMatcher (url: UrlSegment[]) {
  const auth =  applicationInjector.get(AuthService);
  return auth.isUserType('admin') ? ({consumed: [url[0]]}) : null;
}

And now only thing we need is to create applicationInjector in our main module, so we could inject service in our matcher-function;

export let applicationInjector: Injector;

platformBrowserDynamic().bootstrapModule(AppModule).then((componentRef) => {
  applicationInjector = componentRef.injector;
})



回答2:


You can use a Module that handles what module should be load by providing the ROUTES of the RouterModule using the useFactory provider of Angular.

The code could be something like that.

// HandlerModule

@NgModule({
  declarations: [],
  imports: [
    CommonModule,
    RouterModule
  ],
  providers: [
    {
      provide: ROUTES,
      useFactory: configHandlerRoutes,
      deps: [SessionService],
      multi: true
    }
  ]
})


export class HandlerModule {}

export function configHandlerRoutes(sessionService: SessionService) {
  let routes: Routes = [];
  if (sessionService.isLoggedIn()) {
    routes = [
      {
        path: '', loadChildren: () => import('app/member/member.module').then(mod => mod.MemberModule)
      }
    ];
  } else {
    routes = [
      {
        path: '', loadChildren: () => import(app/guest/guest.module).then(mod => mod.GuestModule)
      }
    ];
  }
  return routes;
}

Then in your AppRoutingModule the module of the path '' is going to be the HandlerModule:

// AppRoutingModule

 {
    path: '',
    loadChildren: () => import('app/handler/handler.module').then(mod => mod.HandlerModule)
}

After in the SessionService you have to update the Router.config when the value that provides the method isLoggedIn changes, because the application will only load the page (module) that had loaded the first time. This is because the function “configHandlerRoutes” use by the useFactory provider in the HandlerModule is only executed the first time we navigate to the “” path and after that the Angular Router already know which module he has to load.

In conclusion in the SessionService you have to do:

  export class SessionService {
  private loggedIn: boolean;
  constructor(private router: Router) {
    this.loggedIn = false;
  }

  public isLoggedIn(): boolean {
    return this.loggedIn;
  }

  public setLoggedIn(value: boolean): void {
    const previous = this.loggedIn;
    this.loggedIn = value;
    if (previous === this.loggedIn) {
      return;
    }
    const i = this.router.config.findIndex(x => x.path === '');
    this.router.config.splice(i, 1);
    this.router.config.push(
      {path: '', loadChildren: () => import('app/handler/handler.module').then(mod => mod.HandlerModule)}
    );
  }
}

That's it.

If you want another reference here is an article where they use the same approach: https://medium.com/@german.quinteros/angular-use-the-same-route-path-for-different-modules-or-components-11db75cac455




回答3:


One way to do this will be to route to appropriate area depending on whether the user is logged in or not.

(i.e. whether you open blank route or guest route, it will get redirected appropriately, and back button won't work)

Routes:

{
    path: '',
    loadChildren: 'app/member/member.module#MemberModule',
    canActivate: [LoggedInGuard],
},
{
    path: 'guest',
    loadChildren: 'app/guest/guest.module#GuestModule',
    canActivate: [GuestGuard],
}

LoggedInGuard::

canActivate(route: ActivatedRouteSnapshot, state: RouterStateSnapshot): boolean {
    if(this.sessionService.isLoggedIn()) {
        return true;
    } else {
        // route to 'guest' if not logged in
        this.router.navigate(['/guest'], { replaceUrl: true });
        return false;
    }
}

GuestGuard (with automatic route to MemberComponent if logged in):

canActivate(route: ActivatedRouteSnapshot, state: RouterStateSnapshot): boolean {
    if(this.sessionService.isLoggedIn()) {
        // route to member area if already logged in
        this.router.navigate(['/'], { replaceUrl: true });
        return false;
    } else {
        return true;
    }
}


来源:https://stackoverflow.com/questions/41928727/angular-2-different-components-with-same-route

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