How to create python bytes object from long hex string?

问题

I have a long sequence of hex digits in a string, such as

000000000000484240FA063DE5D0B744ADBED63A81FAEA390000C8428640A43D5005BD44

only much longer, several kilobytes. Is there a builtin way to convert this to a bytes object in python 2.6/3?

回答1:

Works in Python 2.7 and higher including python3:

result = bytearray.fromhex('deadbeef')

Note: There seems to be a bug with the bytearray.fromhex() function in Python 2.6. The python.org documentation states that the function accepts a string as an argument, but when applied, the following error is thrown:

>>> bytearray.fromhex('B9 01EF')
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: fromhex() argument 1 must be unicode, not str`

回答2:

result = bytes.fromhex(some_hex_string)

回答3:

You can do this with the hex codec. ie:

>>> s='000000000000484240FA063DE5D0B744ADBED63A81FAEA390000C8428640A43D5005BD44'
>>> s.decode('hex')
'\x00\x00\x00\x00\x00\x00HB@\xfa\x06=\xe5\xd0\xb7D\xad\xbe\xd6:\x81\xfa\xea9\x00\x00\xc8B\x86@\xa4=P\x05\xbdD'

回答4:

Try the binascii module

from binascii import unhexlify
b = unhexlify(myhexstr)

回答5:

import binascii

binascii.a2b_hex(hex_string)

Thats the way I did it.

回答6:

import binascii

binascii.b2a_hex(obj)

来源：https://stackoverflow.com/questions/443967/how-to-create-python-bytes-object-from-long-hex-string