Use of SqlParameter in SQL LIKE clause not working

问题

I have the following code:

const string Sql = 
    @"select distinct [name] 
      from tblCustomers 
      left outer join tblCustomerInfo on tblCustomers.Id = tblCustomerInfo.CustomerId  
      where (tblCustomer.Name LIKE '%@SEARCH%' OR tblCustomerInfo.Info LIKE '%@SEARCH%');";

using (var command = new SqlCommand(Sql, Connection))
{       
    command.Parameters.AddWithValue("@SEARCH", searchString);
    ...
}

This does not work, I tried this as well:

const string Sql = 
    @"select distinct [name] 
     from tblCustomers 
     left outer join tblCustomerInfo on tblCustomers.Id = tblCustomerInfo.CustomerId  
     where (tblCustomer.Name LIKE @SEARCH OR tblCustomerInfo.Info LIKE @SEARCH );";

using (var command = new SqlCommand(Sql, Connection))
{       
    command.Parameters.AddWithValue("@SEARCH", "'%" + searchString + "%'");
    ...
}

but this does not work as well. What is going wrong? Any suggestions?

回答1:

What you want is:

tblCustomerInfo.Info LIKE '%' + @SEARCH + '%'

(or edit the parameter value to include the % in the first place).

Otherwise, you are either (first sample) searching for the literal "@SEARCH" (not the arg-value), or you are embedding some extra quotes into the query (second sample).

In some ways, it might be easier to have the TSQL just use LIKE @SEARCH, and handle it at the caller:

command.Parameters.AddWithValue("@SEARCH","%" + searchString + "%");

Either approach should work.

回答2:

Instead of using:

const string Sql = 
@"select distinct [name] 
  from tblCustomers 
  left outer join tblCustomerInfo on tblCustomers.Id = tblCustomerInfo.CustomerId  
  where (tblCustomer.Name LIKE '%@SEARCH%' OR tblCustomerInfo.Info LIKE '%@SEARCH%');";

Use this code:

const string Sql = 
@"select distinct [name] 
  from tblCustomers 
  left outer join tblCustomerInfo on tblCustomers.Id = tblCustomerInfo.CustomerId  
  where (tblCustomer.Name LIKE '%' + @SEARCH + '%' OR tblCustomerInfo.Info LIKE '%' + @SEARCH + '%');";

回答3:

Just a little careful with a slight difference between Add and AddWithValue methods. I had the problem below, when I used the Add method and put the wrong SqlType parameter.

nchar and nvarchar can store Unicode characters.
char and varchar cannot store Unicode characters.

For example:

string query = " ... WHERE stLogin LIKE @LOGIN ";

SqlParameter p = new SqlParameter("@LOGIN", SqlDbType.Char, 255) 
{ 
    Value = "%" + login + "%" 
};

command.Parameters.AddWithValue(p.ParameterName, p.Value); //works fine!!!

command.Parameters.Add(p); // won't work

When I changed the SqlType to NVarChar, the two methods worked fine to me.

SqlParameter p = new SqlParameter("@LOGIN", SqlDbType.NVarChar, 255) 
{ 
    Value = "%" + login + "%" 
};

command.Parameters.AddWithValue(p.ParameterName, p.Value); //worked fine!!!

command.Parameters.Add(p); //worked fine!!!

回答4:

You could do LIKE @SEARCH and in your C# code, do

searchString = "%" + searchString + "%"

来源：https://stackoverflow.com/questions/665129/use-of-sqlparameter-in-sql-like-clause-not-working

标签

sql-server

tsql

ado.net

sql-like