Convert an iOS objective c object to a JSON string

问题

I have an objective C class like,

@interface message : NSObject {
 NSString *from;
 NSString *date;
 NSString *msg;
}

I have an NSMutableArray of instances of this message class. I want serialize all the instances in the NSMutableArray into a JSON file, using the new JSONSerialization APIs in iOS 5 SDK. How can I do this ?

Is creating a NSDictionary of each key, by iterating through each instance of the elements in the NSArray ? Can someone help with code of how to solve this ? I am not able to get good results in Google, as "JSON" skews the results to server-side calls and transfer of data instead of serialization. Thanks a lot.

EDIT:

NSError *writeError = nil; 
NSData *jsonData = [NSJSONSerialization dataWithJSONObject:notifications options:NSJSONWritingPrettyPrinted error:&writeError];
NSString *jsonString = [[NSString alloc] initWithData:jsonData encoding:NSUTF8StringEncoding]; 
NSLog(@"JSON Output: %@", jsonString);

回答1:

EDIT: I have made a dummy app that should be a good example for you.

I create a Message class from your code snippet;

//Message.h
@interface Message : NSObject {
    NSString *from_;
    NSString *date_;
    NSString *msg_;
}

@property (nonatomic, retain) NSString *from;
@property (nonatomic, retain) NSString *date;
@property (nonatomic, retain) NSString *msg;

-(NSDictionary *)dictionary;

@end

//Message.m
#import "Message.h"

@implementation Message

@synthesize from = from_;
@synthesize date = date_;
@synthesize msg = mesg_;

-(void) dealloc {
    self.from = nil;
    self.date = nil;
    self.msg = nil;
    [super dealloc];
}

-(NSDictionary *)dictionary {
    return [NSDictionary dictionaryWithObjectsAndKeys:self.from,@"from",self.date,    @"date",self.msg, @"msg", nil];
}

Then I set up an NSArray of two messages in the AppDelegate. The trick is that not only does the top level object (notifications in your case) need to be serializable but so do all the elements that notifications contains: Thats why I created the dictionary method in the Message class.

//AppDelegate.m
...
Message* message1 = [[Message alloc] init];
Message* message2 = [[Message alloc] init];

message1.from = @"a";
message1.date = @"b";
message1.msg = @"c";

message2.from = @"d";
message2.date = @"e";
message2.msg = @"f";

NSArray* notifications = [NSArray arrayWithObjects:message1.dictionary, message2.dictionary, nil];
[message1 release];
[message2 release];


NSError *writeError = nil; 
NSData *jsonData = [NSJSONSerialization dataWithJSONObject:notifications options:NSJSONWritingPrettyPrinted error:&writeError];
NSString *jsonString = [[NSString alloc] initWithData:jsonData encoding:NSUTF8StringEncoding]; 
NSLog(@"JSON Output: %@", jsonString);

@end

The output when I run the application is thus:

2012-05-11 11:58:36.018 stack[3146:f803] JSON Output: [ { "msg" : "c", "from" : "a", "date" : "b" }, { "msg" : "f", "from" : "d", "date" : "e" } ]

ORIGINAL ANSWER:

Is this the documentation you are looking for?

回答2:

Now you can solve this problem easily using JSONModel. JSONModel is a library that generically serialize/deserialize your object based on Class. You can even use non-nsobject based for property like int, short and float. It can also cater nested-complex JSON. It handles error checking for you.

Deserialize example. in header file:

#import "JSONModel.h"

@interface Message : JSONModel 
@property (nonatomic, strong) NSString* from;
@property (nonatomic, strong) NSString* date;
@property (nonatomic, strong) NSString* message;
@end

in implementation file:

#import "JSONModelLib.h"
#import "yourPersonClass.h"

NSString *responseJSON = /*from somewhere*/;
Message *message = [[Message alloc] initWithString:responseJSON error:&err];
if (!err)
{
   NSLog(@"%@  %@  %@", message.from, message.date, message.message):
}

Serialize Example. In implementation file:

#import "JSONModelLib.h"
#import "yourPersonClass.h"

Message *message = [[Message alloc] init];
message.from = @"JSON beast";
message.date = @"2012";
message.message = @"This is the best method available so far";

NSLog(@"%@", [person toJSONString]);

回答3:

Note: This will only work with serializable objects. This answer was provided above in an edit to the question itself, but I always look for answers in the "answers" section myself ;-)

- (NSString*) convertObjectToJson:(NSObject*) object
{
    NSError *writeError = nil;

    NSData *jsonData = [NSJSONSerialization dataWithJSONObject:object options:NSJSONWritingPrettyPrinted error:&writeError];
    NSString *result = [[NSString alloc] initWithData:jsonData encoding:NSUTF8StringEncoding];

    return result;
}

回答4:

Here is a library i used in my projects BWJSONMatcher, which can help you easily match your json string up with your data model with no more than one line of code.

...
NSString *jsonString = @"{your-json-string}";
YourValueObject *dataModel = [YourValueObject fromJSONString:jsonString];

NSDictionary *jsonObject = @{your-json-object};
YourValueObject *dataModel = [YourValueObject fromJSONObject:jsonObject];
...
YourValueObject *dataModel = instance-of-your-value-object;
NSString *jsonString = [dataModel toJSONString];
NSDictionary *jsonObject = [dataModel toJSONObject];
...

来源：https://stackoverflow.com/questions/10548429/convert-an-ios-objective-c-object-to-a-json-string

标签

ios

json

serialization

nsarray