问题
how to check the text of edittext is email address or not without using javascript and regular expression?
Here I used inputtype="textEmailAddress" this is working but no error message is display.
回答1:
/**
* method is used for checking valid email id format.
*
* @param email
* @return boolean true for valid false for invalid
*/
public static boolean isEmailValid(String email) {
String expression = "^[\\w\\.-]+@([\\w\\-]+\\.)+[A-Z]{2,4}$";
Pattern pattern = Pattern.compile(expression, Pattern.CASE_INSENSITIVE);
Matcher matcher = pattern.matcher(email);
return matcher.matches();
}
Pass your edit text string in this function .
for right email verification you need server side authentication
Note there is now a built-in method in Android, see answers below.
回答2:
On Android 2.2+ use this:
boolean isEmailValid(CharSequence email) {
return android.util.Patterns.EMAIL_ADDRESS.matcher(email).matches();
}
for example:
EditText emailid = (EditText) loginView.findViewById(R.id.login_email);
String getEmailId = emailid.getText().toString();
// Check if email id is valid or not
if (!isEmailValid(getEmailId)){
new CustomToast().Show_Toast(getActivity(), loginView,
"Your Email Id is Invalid.");
}
回答3:
Please follow the following Steps
Step 1 :
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:tools="http://schemas.android.com/tools"
android:layout_width="match_parent"
android:layout_height="match_parent"
tools:context=".MainActivity" >
<EditText
android:id="@+id/editText_email"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:layout_marginLeft="20dp"
android:layout_marginRight="20dp"
android:layout_below="@+id/textView_email"
android:layout_marginTop="40dp"
android:hint="Email Adderess"
android:inputType="textEmailAddress" />
<TextView
android:id="@+id/textView_email"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:layout_alignParentTop="true"
android:layout_centerHorizontal="true"
android:layout_marginTop="30dp"
android:text="Email Validation Example" />
</RelativeLayout>
Step 2:
import android.app.Activity;
import android.os.Bundle;
import android.text.Editable;
import android.text.TextWatcher;
import android.widget.EditText;
Step 3:
public class MainActivity extends Activity {
private EditText email;
private String valid_email;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
initilizeUI();
}
/**
* This method is used to initialize UI Components
*/
private void initilizeUI() {
// TODO Auto-generated method stub
email = (EditText) findViewById(R.id.editText_email);
email.addTextChangedListener(new TextWatcher() {
@Override
public void onTextChanged(CharSequence s, int start, int before,
int count) {
// TODO Auto-generated method stub
}
@Override
public void beforeTextChanged(CharSequence s, int start, int count,
int after) {
// TODO Auto-generated method stub
}
@Override
public void afterTextChanged(Editable s) {
// TODO Auto-generated method stub
// TODO Auto-generated method stub
Is_Valid_Email(email); // pass your EditText Obj here.
}
public void Is_Valid_Email(EditText edt) {
if (edt.getText().toString() == null) {
edt.setError("Invalid Email Address");
valid_email = null;
} else if (isEmailValid(edt.getText().toString()) == false) {
edt.setError("Invalid Email Address");
valid_email = null;
} else {
valid_email = edt.getText().toString();
}
}
boolean isEmailValid(CharSequence email) {
return android.util.Patterns.EMAIL_ADDRESS.matcher(email)
.matches();
} // end of TextWatcher (email)
});
}
}
回答4:
I wrote a library that extends EditText which supports natively some validation methods and is actually very flexible.
Current, as I write, natively supported (through xml attributes) validation methods are:
- regexp: for custom regexp
- numeric: for an only numeric field
- alpha: for an alpha only field
- alphaNumeric: guess what?
- email: checks that the field is a valid email
- creditCard: checks that the field contains a valid credit card using Luhn Algorithm
- phone: checks that the field contains a valid phone number
- domainName: checks that field contains a valid domain name ( always passes the test in API Level < 8 )
- ipAddress: checks that the field contains a valid ip address webUrl: checks that the field contains a valid url ( always passes the test in API Level < 8 )
- nocheck: It does not check anything. (Default)
You can check it out here: https://github.com/vekexasia/android-form-edittext
Hope you enjoy it :)
In the page I linked you'll be able to find also an example for email validation. I'll copy the relative snippet here:
<com.andreabaccega.widget.FormEditText
style="@android:style/Widget.EditText"
whatever:test="email"
android:id="@+id/et_email"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:hint="@string/hint_email"
android:inputType="textEmailAddress"
/>
There is also a test app showcasing the library possibilities.
This is a screenshot of the app validating the email field.
回答5:
As mentioned in one of the answers you can use the Patterns class as below:
public final static boolean isValidEmail(CharSequence target) {
if (target == null)
return false;
return android.util.Patterns.EMAIL_ADDRESS.matcher(target).matches();
}
By chance if you are even supporting API level less than 8, then you can simply copy the Patterns.java file into your project and reference it. You can get the source code for Patterns.java from this link
回答6:
The following code should be useful to you.
String email;
check.setOnClickListener(new OnClickListener() {
public void onClick(View arg0) {
checkEmail(email);
if (checkMail) {
System.out.println("Valid mail Id");
}
}
});
}
}
public static boolean checkEmail(String email) {
Pattern EMAIL_ADDRESS_PATTERN = Pattern
.compile("[a-zA-Z0-9+._%-+]{1,256}" + "@"
+ "[a-zA-Z0-9][a-zA-Z0-9-]{0,64}" + "(" + "."
+ "[a-zA-Z0-9][a-zA-Z0-9-]{0,25}" + ")+");
return EMAIL_ADDRESS_PATTERN.matcher(email).matches();
}
回答7:
here email is your email-id.
public boolean validateEmail(String email) {
Pattern pattern;
Matcher matcher;
String EMAIL_PATTERN = "^[_A-Za-z0-9-]+(\\.[_A-Za-z0-9-]+)*@[A-Za-z0-9]+(\\.[A-Za-z0-9]+)*(\\.[A-Za-z]{2,})$";
pattern = Pattern.compile(EMAIL_PATTERN);
matcher = pattern.matcher(email);
return matcher.matches();
}
回答8:
Apache Commons Validator can be used as mentioned in the other answers.
Step:1)Download the jar file from here
Step:2)Add it into your project libs
The import:
import org.apache.commons.validator.routines.EmailValidator;
The code:
String email = "myName@example.com";
boolean valid = EmailValidator.getInstance().isValid(email);
and to allow local addresses::
boolean allowLocal = true;
boolean valid = EmailValidator.getInstance(allowLocal).isValid(email);
回答9:
A simple method
private boolean isValidEmail(String email)
{
String emailRegex ="^[_A-Za-z0-9-\\+]+(\\.[_A-Za-z0-9-]+)*@[A-Za-z0-9-]+(\\.[A-Za-z0-9]+)*(\\.[A-Za-z]{2,})$";
if(email.matches(emailRegex))
{
return true;
}
return false;
}
回答10:
I Hope this code is beneficial for you
public class Register extends Activity
{
EditText FirstName, PhoneNo, EmailId,weight;
Button Register;
private static final Pattern EMAIL_PATTERN = Pattern
.compile("^[_A-Za-z0-9-]+(\\.[_A-Za-z0-9-]+)*@[A-Za-z0-9]+(\\.[A-Za-z0-9]+)*(\\.[A-Za-z]{2,})$");
private static final Pattern USERFIRSTNAME_PATTERN = Pattern
.compile("[a-zA-Z0-9]{1,250}");
private static final Pattern PHONE_PATTERN = Pattern
.compile("[a-zA-Z0-9]{1,250}");
@Override
public void onCreate(Bundle savedInstanceState) {
// TODO Auto-generated method stub
super.onCreate(savedInstanceState);
setContentView(R.layout.register);
Register=(Button) findViewById(R.id.register);
FirstName=(EditText)findViewById(R.id.person_firstname);
PhoneNo =(EditText)findViewById(R.id.phone_no);
EmailId=(EditText)findViewById(R.id.email_id);
weight=(EditText) findViewById(R.id.weight);
Register.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
sFirstName= FirstName.getText().toString();
sPhoneNo= PhoneNo.getText().toString();
sEmailId= EmailId.getText().toString();
sweight= weight.getText().toString();
if(sFirstName.equals("")||sPhoneNo.equals("")||sEmailId.equals("")||sweight.equals(""))
{
if ((!CheckUsername(sFirstName)))
{
Toast.makeText(Register.this, "FirstName can not be null",Toast.LENGTH_LONG).show();
}
else if ((!Checkphoneno(sPhoneNo)))
{
Toast.makeText(Register.this, "ENTER VALID mobile no ",Toast.LENGTH_LONG).show();
}
else if ((!CheckEmail(sEmailId)))
{
Toast.makeText(Register.this, "ENTER VALID EMAIL ID",Toast.LENGTH_LONG).show();
}
else if ((!Checkweight(sweight)))
{
Toast.makeText(Register.this, "ENTER Weight in kg",Toast.LENGTH_LONG).show();
}
}
}
private boolean CheckEmail(String sEmailId) {
return EMAIL_PATTERN.matcher(sEmailId).matches();
}
private boolean CheckUsername(String sFirstName) {
return USERFIRSTNAME_PATTERN.matcher(sFirstName).matches();
}
private boolean Checkphoneno(String sPhoneNo) {
return PHONE_PATTERN.matcher(sPhoneNo).matches();
}
private boolean Checkweight(String sweight) {
return Weight_PATTERN.matcher(sweight).matches();
}
});
回答11:
public static boolean isEmailValid(String email) {
boolean isValid = false;
String expression = "^(([\\w-]+\\.)+[\\w-]+|([a-zA-Z]{1}|[\\w-]{2,}))@"
+ "((([0-1]?[0-9]{1,2}|25[0-5]|2[0-4][0-9])\\.([0-1]?"
+ "[0-9]{1,2}|25[0-5]|2[0-4][0-9])\\."
+ "([0-1]?[0-9]{1,2}|25[0-5]|2[0-4][0-9])\\.([0-1]?"
+ "[0-9]{1,2}|25[0-5]|2[0-4][0-9])){1}|"
+ "([a-zA-Z]+[\\w-]+\\.)+[a-zA-Z]{2,4})$";
// "^[\\w\\.-]+@([\\w\\-]+\\.)+[A-Z]{2,4}$";
CharSequence inputStr = email;
Pattern pattern = Pattern.compile(expression, Pattern.CASE_INSENSITIVE);
Matcher matcher = pattern.matcher(inputStr);
if (!matcher.matches()) {
isValid = true;
}
return isValid;
}
回答12:
for email validation try this.
public boolean checkemail(String email)
{
Pattern pattern = Pattern.compile(".+@.+\\.[a-z]+");
Matcher matcher = pattern.matcher(email);
return matcher.matches();
}
回答13:
You can check it by regular expression
public boolean isValid(String strEmail)
{
pattern = Pattern.compile("^[_A-Za-z0-9-\\+]+(\\.[_A-Za-z0-9-]+)*@[A-Za-z0-9-]+(\\.[A-Za-z0-9]+)*(\\.[A-Za-z]{2,})$");
matcher = pattern.matcher(strEmail);
if (strEmail.isEmpty()) {
return false;
} else if (!matcher.matches()) {
return false;
}
else
{
return true;
}
}
回答14:
private boolean isValidEmailID(String email) {
String PATTERN = "^[_A-Za-z0-9-\\+]+(\\.[_A-Za-z0-9-]+)*@"+ "[A-Za-z0-9-]+(\\.[A-Za-z0-9]+)*(\\.[A-Za-z]{2,})$";
Pattern pattern = Pattern.compile(PATTERN);
Matcher matcher = pattern.matcher(email);
return matcher.matches();
}
For more validation click here
回答15:
With android.util.Patterns and Kotlin it's very simple. One line function which return Boolean value.
fun validateEmail(email: String) = Patterns.EMAIL_ADDRESS.matcher(email)
回答16:
In your case you can use the android.util.Patterns package.
EditText email = (EditText)findViewById(R.id.user_email);
if(Patterns.EMAIL_ADDRESS.matcher(email.getText().toString()).matches())
Toast.makeText(this, "Email is VALID.", Toast.LENGTH_SHORT).show();
else
Toast.makeText(this, "Email is INVALID.", Toast.LENGTH_SHORT).show();
来源：https://stackoverflow.com/questions/6119722/how-to-check-edittexts-text-is-email-address-or-not