How do you make git diff only show the difference between two commits, excluding the other commits in-between?
you can simply pass the 2 commits to git diff like :
-> git diff 0da94be 59ff30c > my.patch
-> git apply my.patch
Asking for the difference /between/ two commits without including the commits in-between makes little sense. Commits are just snapshots of the contents of the repository; asking for the difference between two necessarily includes them. So the question then is, what are you really looking for?
As William suggested, cherry-picking can give you the delta of a single commit rebased on top of another. That is:
$ git checkout 012345
$ git cherry-pick -n abcdef
$ git diff --cached
This takes commit 'abcdef', compares it to its immediate ancestor, then applies that difference on top of '012345'. This new difference is then shown - the only change is the context comes from '012345' rather than 'abcdef's immediate ancestor. Of course, you may get conflicts and etc, so it's not a very useful process in most cases.
If you're just interested in abcdef itself, you can do:
$ git log -u -1 abcdef
This compares abcdef to its immediate ancestor, alone, and is usually what you want.
And of course
$ git diff 012345..abcdef
gives you all differences between those two commits.
It would help to get a better idea of what you're trying to achieve - as I mentioned, asking for the difference between two commits without what's in between doesn't actually make sense.
To compare two git commits 12345 and abcdef as patches one can use the diff command as
diff <(git show 123456) <(git show abcdef)
git diff <a-commit> <another-commit> path
Example:
git diff commit1 commit2 config/routes.rb
It shows the difference on that file between those commits.
Let's say you have this
A
|
B A0
| |
C D
\ /
|
...
And you want to make sure that A is the same as A0.
This will do the trick:
$ git diff B A > B-A.diff
$ git diff D A0 > D-A0.diff
$ diff B-A.diff D-A0.diff
Suppose you want to see the difference between commits 012345 and abcdef. The following should do what you want:
$ git checkout 012345 $ git cherry-pick -n abcdef $ git diff --cached
For checking complete changes:
git diff <commit_Id_1> <commit_Id_2>
For checking only the changed/added/deleted files:
git diff <commit_Id_1> <commit_Id_2> --name-only
NOTE: For checking diff without commit in between, you don't need to put the commit ids.
What about this:
git diff abcdef 123456 | less
It's handy to just pipe it to less if you want to compare many different diffs on the fly.
My alias settings in ~/.bashrc file for git diff:
alias gdca='git diff --cached' # diff between your staged file and the last commit
alias gdcc='git diff HEAD{,^}' # diff between your recent tow commits
English is not my native language, please excuse typing errors
I wrote a script which displays diff between two commits, works well on Ubuntu.
https://gist.github.com/jacobabrahamb4/a60624d6274ece7a0bd2d141b53407bc
#!/usr/bin/env python
import sys, subprocess, os
TOOLS = ['bcompare', 'meld']
def getTool():
for tool in TOOLS:
try:
out = subprocess.check_output(['which', tool]).strip()
if tool in out:
return tool
except subprocess.CalledProcessError:
pass
return None
def printUsageAndExit():
print 'Usage: python bdiff.py <project> <commit_one> <commit_two>'
print 'Example: python bdiff.py <project> 0 1'
print 'Example: python bdiff.py <project> fhejk7fe d78ewg9we'
print 'Example: python bdiff.py <project> 0 d78ewg9we'
sys.exit(0)
def getCommitIds(name, first, second):
commit1 = None
commit2 = None
try:
first_index = int(first) - 1
second_index = int(second) - 1
if int(first) < 0 or int(second) < 0:
print "Cannot handle negative values: "
sys.exit(0)
logs = subprocess.check_output(['git', '-C', name, 'log', '--oneline', '--reverse']).split('\n')
if first_index >= 0:
commit1 = logs[first_index].split(' ')[0]
if second_index >= 0:
commit2 = logs[second_index].split(' ')[0]
except ValueError:
if first != '0':
commit1 = first
if second != '0':
commit2 = second
return commit1, commit2
def validateCommitIds(name, commit1, commit2):
if commit1 == None and commit2 == None:
print "Nothing to do, exit!"
return False
try:
if commit1 != None:
subprocess.check_output(['git', '-C', name, 'cat-file', '-t', commit1]).strip()
if commit2 != None:
subprocess.check_output(['git', '-C', name, 'cat-file', '-t', commit2]).strip()
except subprocess.CalledProcessError:
return False
return True
def cleanup(commit1, commit2):
subprocess.check_output(['rm', '-rf', '/tmp/'+(commit1 if commit1 != None else '0'), '/tmp/'+(commit2 if commit2 != None else '0')])
def checkoutCommit(name, commit):
if commit != None:
subprocess.check_output(['git', 'clone', name, '/tmp/'+commit])
subprocess.check_output(['git', '-C', '/tmp/'+commit, 'checkout', commit])
else:
subprocess.check_output(['mkdir', '/tmp/0'])
def compare(tool, commit1, commit2):
subprocess.check_output([tool, '/tmp/'+(commit1 if commit1 != None else '0'), '/tmp/'+(commit2 if commit2 != None else '0')])
if __name__=='__main__':
tool = getTool()
if tool == None:
print "No GUI diff tools"
sys.exit(0)
if len(sys.argv) != 4:
printUsageAndExit()
name, first, second = None, 0, 0
try:
name, first, second = sys.argv[1], sys.argv[2], sys.argv[3]
except IndexError:
printUsageAndExit()
commit1, commit2 = getCommitIds(name, first, second)
if not validateCommitIds(name, commit1, commit2):
sys.exit(0)
cleanup(commit1, commit2)
checkoutCommit(name, commit1)
checkoutCommit(name, commit2)
try:
compare(tool, commit1, commit2)
except KeyboardInterrupt:
pass
finally:
cleanup(commit1, commit2)
sys.exit(0)
Since Git 2.19, you can simply use:
git range-diff rev1...rev2
- compare two commit trees, starting by their common ancestor
or
git range-diff rev1~..rev1 rev2~..rev2
- compare of changes introduced by 2 given commits
来源：https://stackoverflow.com/questions/1191282/how-to-see-the-changes-between-two-commits-without-commits-in-between