问题
I have a column named sequence. The data in this column looks like 1, 2, 3, 4, 5, 7, 9, 10, 15.
I need to find the missing sequence numbers from the table. What SQL query will find the missing sequence numbers from my table? I am expecting results like
Missing numbers
---------------
6
8
11
12
13
14
I am using only one table. I tried the query below, but am not getting the results I want.
select de.sequence + 1 as sequence from dataentry as de
left outer join dataentry as de1 on de.sequence + 1 = de1.sequence
where de1.sequence is null order by sequence asc;
回答1:
How about something like:
select (select isnull(max(val)+1,1) from mydata where val < md.val) as [from],
md.val - 1 as [to]
from mydata md
where md.val != 1 and not exists (
select 1 from mydata md2 where md2.val = md.val - 1)
giving summarised results:
from to
----------- -----------
6 6
8 8
11 14
回答2:
I know this is a very old post but I wanted to add this solution that I found HERE so that I can find it easier:
WITH Missing (missnum, maxid)
AS
(
SELECT 1 AS missnum, (select max(id) from @TT)
UNION ALL
SELECT missnum + 1, maxid FROM Missing
WHERE missnum < maxid
)
SELECT missnum
FROM Missing
LEFT OUTER JOIN @TT tt on tt.id = Missing.missnum
WHERE tt.id is NULL
OPTION (MAXRECURSION 0);
回答3:
Try with this:
declare @min int
declare @max int
select @min = min(seq_field), @max = max(seq_field) from [Table]
create table #tmp (Field_No int)
while @min <= @max
begin
if not exists (select * from [Table] where seq_field = @min)
insert into #tmp (Field_No) values (@min)
set @min = @min + 1
end
select * from #tmp
drop table #tmp
回答4:
The best solutions are those that use a temporary table with the sequence. Assuming you build such a table, LEFT JOIN with NULL check should do the job:
SELECT #sequence.value
FROM #sequence
LEFT JOIN MyTable ON #sequence.value = MyTable.value
WHERE MyTable.value IS NULL
But if you have to repeat this operation often (and more then for 1 sequence in the database), I would create a "static-data" table and have a script to populate it to the MAX(value) of all the tables you need.
回答5:
SELECT CASE WHEN MAX(column_name) = COUNT(*)
THEN CAST(NULL AS INTEGER)
-- THEN MAX(column_name) + 1 as other option
WHEN MIN(column_name) > 1
THEN 1
WHEN MAX(column_name) <> COUNT(*)
THEN (SELECT MIN(column_name)+1
FROM table_name
WHERE (column_name+ 1)
NOT IN (SELECT column_name FROM table_name))
ELSE NULL END
FROM table_name;
回答6:
Here is a script to create a stored procedure that returns missing sequential numbers for a given date range.
CREATE PROCEDURE dbo.ddc_RolledBackOrders
-- Add the parameters for the stored procedure here
@StartDate DATETIME ,
@EndDate DATETIME
AS
BEGIN
SET NOCOUNT ON;
DECLARE @Min BIGINT
DECLARE @Max BIGINT
DECLARE @i BIGINT
IF OBJECT_ID('tempdb..#TempTable') IS NOT NULL
BEGIN
DROP TABLE #TempTable
END
CREATE TABLE #TempTable
(
TempOrderNumber BIGINT
)
SELECT @Min = ( SELECT MIN(ordernumber)
FROM dbo.Orders WITH ( NOLOCK )
WHERE OrderDate BETWEEN @StartDate AND @EndDate)
SELECT @Max = ( SELECT MAX(ordernumber)
FROM dbo.Orders WITH ( NOLOCK )
WHERE OrderDate BETWEEN @StartDate AND @EndDate)
SELECT @i = @Min
WHILE @i <= @Max
BEGIN
INSERT INTO #TempTable
SELECT @i
SELECT @i = @i + 1
END
SELECT TempOrderNumber
FROM #TempTable
LEFT JOIN dbo.orders o WITH ( NOLOCK ) ON tempordernumber = o.OrderNumber
WHERE o.OrderNumber IS NULL
END
GO
回答7:
This is my interpretation of this issue, placing the contents in a Table variable that I can easily access in the remainder of my script.
DECLARE @IDS TABLE (row int, ID int)
INSERT INTO @IDS
select ROW_NUMBER() OVER (ORDER BY x.[Referred_ID]), x.[Referred_ID] FROM
(SELECT b.[Referred_ID] + 1 [Referred_ID]
FROM [catalog].[dbo].[Referrals] b) as x
LEFT JOIN [catalog].[dbo].[Referrals] a ON x.[Referred_ID] = a.[Referred_ID]
WHERE a.[Referred_ID] IS NULL
select * from @IDS
回答8:
Just for fun, I decided to post my solution.
I had an identity column in my table and I wanted to find missing invoice numbers.
I reviewed all the examples I could find but they were not elegant enough.
CREATE VIEW EENSkippedInvoicveNo
AS
SELECT CASE WHEN MSCNT = 1 THEN CAST(MSFIRST AS VARCHAR (8)) ELSE
CAST(MSFIRST AS VARCHAR (8)) + ' - ' + CAST(MSlAST AS VARCHAR (8)) END AS MISSING,
MSCNT, INV_DT FROM (
select invNo+1 as Msfirst, inv_no -1 as Mslast, inv_no - invno -1 as msCnt, dbo.fmtdt(Inv_dt) AS INV_dT
from (select inv_no as invNo, a4glidentity + 1 as a4glid
from oehdrhst_sql where inv_dt > 20140401) as s
inner Join oehdrhst_sql as h
on a4glid = a4glidentity
where inv_no - invno <> 1
) AS SS
回答9:
DECLARE @MaxID INT = (SELECT MAX(timerecordid) FROM dbo.TimeRecord)
SELECT SeqID AS MissingSeqID
FROM (SELECT ROW_NUMBER() OVER (ORDER BY column_id) SeqID from sys.columns) LkUp
LEFT JOIN dbo.TimeRecord t ON t.timeRecordId = LkUp.SeqID
WHERE t.timeRecordId is null and SeqID < @MaxID
I found this answer here: http://sql-developers.blogspot.com/2012/10/how-to-find-missing-identitysequence.html
I was looking for a solution and found many answers. This is the one I used and it worked very well. I hope this helps anyone looking for a similar answer.
回答10:
-- This will return better Results
-- ----------------------------------
;With CTERange
As (
select (select isnull(max(ArchiveID)+1,1) from tblArchives where ArchiveID < md.ArchiveID) as [from],
md.ArchiveID - 1 as [to]
from tblArchives md
where md.ArchiveID != 1 and not exists (
select 1 from tblArchives md2 where md2.ArchiveID = md.ArchiveID - 1)
) SELECT [from], [to], ([to]-[from])+1 [total missing]
From CTERange
ORDER BY ([to]-[from])+1 DESC;
from to total missing
------- ------- --------------
6 6 1
8 8 1
11 14 4
回答11:
Aren't all given solutions way too complex? wouldn't this be much simpler:
SELECT *
FROM (SELECT row_number() over(order by number) as N from master..spt_values) t
where N not in (select 1 as sequence union
select 2 union
select 3 union
select 4 union
select 5 union
select 7 union
select 10 union
select 15
)
回答12:
DECLARE @TempSujith TABLE
(MissingId int)
Declare @Id Int
DECLARE @mycur CURSOR
SET @mycur = CURSOR FOR Select Id From tbl_Table
OPEN @mycur
FETCH NEXT FROM @mycur INTO @Id
Declare @index int
Set @index = 1
WHILE @@FETCH_STATUS = 0
BEGIN
if (@index < @Id)
begin
while @index < @Id
begin
insert into @TempSujith values (@index)
set @index = @index + 1
end
end
set @index = @index + 1
FETCH NEXT FROM @mycur INTO @Id
END
Select Id from tbl_Table
select MissingId from @TempSujith
回答13:
Create a useful Tally table:
-- can go up to 4 million or 2^22
select top 100000 identity(int, 1, 1) Id
into Tally
from master..spt_values
cross join master..spt_values
Index it, or make that single column as PK. Then use EXCEPT to get your missing number.
select Id from Tally where Id <= (select max(Id) from TestTable)
except
select Id from TestTable
回答14:
You could also solve using something like a CTE to generate the full sequence:
create table #tmp(sequence int) insert into #tmp(sequence) values (1) insert into #tmp(sequence) values (2) insert into #tmp(sequence) values (3) insert into #tmp(sequence) values (5) insert into #tmp(sequence) values (6) insert into #tmp(sequence) values (8) insert into #tmp(sequence) values (10) insert into #tmp(sequence) values (11) insert into #tmp(sequence) values (14)
DECLARE @max INT
SELECT @max = max(sequence) from #tmp;
with full_sequence
(
Sequence
)
as
(
SELECT 1 Sequence
UNION ALL
SELECT Sequence + 1
FROM full_sequence
WHERE Sequence < @max
)
SELECT
full_sequence.sequence
FROM
full_sequence
LEFT JOIN
#tmp
ON
full_sequence.sequence = #tmp.sequence
WHERE
#tmp.sequence IS NULL
Hmmmm - the formatting is not working on here for some reason? Can anyone see the problem?
来源：https://stackoverflow.com/questions/1057389/sql-query-to-find-missing-sequence-numbers