Group by & count function in sqlalchemy

喜你入骨 提交于 2019-12-17 03:25:27

问题


I want a "group by and count" command in sqlalchemy. How can I do this?


回答1:


The documentation on counting says that for group_by queries it is better to use func.count():

from sqlalchemy import func
session.query(Table.column, func.count(Table.column)).group_by(Table.column).all()



回答2:


You can also count on multiple groups and their intersection:

self.session.query(func.count(Table.column1),Table.column1, Table.column2).group_by(Table.column1, Table.column2).all()

The query above will return counts for all possible combinations of values from both columns.




回答3:


If you are using Table.query property:

from sqlalchemy import func
Table.query.with_entities(Table.column, func.count(Table.column)).group_by(Table.column).all()

If you are using session.query() method (as stated in miniwark's answer):

from sqlalchemy import func
session.query(Table.column, func.count(Table.column)).group_by(Table.column).all()


来源:https://stackoverflow.com/questions/1052148/group-by-count-function-in-sqlalchemy

易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!