问题
The following fails and I don't understand why:
$ echo "#!"
the following also fails with the same error message:
$ echo "\#!"
the error message:
-bash: !": event not found
Why does it fail? How should the echo be done instead?
回答1:
The ! character is used for csh-style history expansion.
If you do not use this feature, set +o histexpand (aka set +H) turns off this behavior. It is turned off for scripts, but often enabled for interactive use. In such cases, my personal recommendation is to turn it off permanently by adding set +o histexpand to your .bash_profile (or .bashrc if you don't have a .bash_profile; this is more complex than I want to try to fit into a parenthetical).
As a workaround, if for some reason you cannot or don't want to turn off and forget about this legacy csh feature, you can use single quotes instead of double quotes -- keeping in mind, of course, their different semantics. If you need to combine quoting with variable interpolation, for example, you can change
echo "#!$SHELL" # oops, history expansion breaks this
into
echo '#!'"$SHELL"
(notice the adjacent single-quoted and double-quoted strings; after the shell is done with this, the quotes will be removed and the string #! will be output next to the value of the variable SHELL with no space between them) or a number of other common workarounds like
printf '#!%s\n' "$SHELL"
回答2:
By default, bash supports csh compatible history-expansion.
In bash
echo #!
will only print a newline, as # starts a comment.
In
echo "#!"
the # is part of the string started with ". Such strings are still inspected by bash for special characters. ! is a special character iff it is followed by any other text.
-bash: !": event not found
In this case, bash expects the !" token to refer to a previous command in shell history starting with ", and does not find one. All by itself, ! will not trigger this behaviour:
$ echo \# !
# !
$ echo fee ! fie
fee ! fie
Finally,
$ echo !echo
produces two lines, the first line is printed by the shell to show how the pattern above expands to:
echo echo '# !'
while the second line is just the result of executing the expanded command: echo # !
See Also: The Bash man page on History Expansion
回答3:
echo '#!'
Basically, with double quotes (") aka "weak quoting", Bash does some wacky things with the string, like variable substitution. With single (') aka "strong quoting" the string is taken literally.
See e.g. here for a more in-depth explanation of quoting.
回答4:
Another workaround may be to put an extra space after the "!" :
# echo "#! "
#!
回答5:
In my case all commands are working. Maybe you can specify your environment.
$ echo "\#\!"
\#\!
$ echo "#!"
echo "#"
#
$ echo "#!"
echo "#"
#
$ echo $BASH_VERSION
3.2.48(1)-release
来源：https://stackoverflow.com/questions/11816122/echo-fails-event-not-found