Achieving ROW_NUMBER / PARTITION BY in MS Access

Question

How to achieve the Row number over partition by in the MS access .I Google but cant find information can you please how to do this

RowNumber Over(Partition by city Order By EmployeeID)

My Data looks like this

DOC_TYPE    Ino
3a  1800xxc1
3b  1810xxc2
3c  1700xxc3
3a  1700xxc4
3a  1800xxc5
3a  1800xxc6
3b  1800xxc7

I need Like this

DOC_TYPE    Ino Seq
3a  1800xxc1    1
3a  1700xxc4    2
3a  1800xxc5    3
3a  1800xxc6    4
3b  1810xxc2    1
3b  1800xxc7    2
3c  1700xxc3    1

this is my Query

SELECT t1.RT_TAXCODE, t1.INV_NO, COUNT(*) AS Sno
FROM GroupByTAXCODE AS t1 INNER JOIN GroupByTAXCODE AS t2 ON (t2.RT_TAXCODE = t1.RT_TAXCODE) AND (t2.Inv_no <= t1.Inv_no)
GROUP BY t1.RT_TAXCODE, t1.INV_NO
HAVING COUNT(*)=1
ORDER BY 1, 3;

This is taking more time as f 30 seconds

Answer 1

In many cases we can achieve a similar result by performing an unequal self-join on the table and aggregating the results. For example, for data in a table named [MyData]

Ino  TYPE      DOC
---  --------  ---
  1  1800xxc1  3a 
  2  1810xxc2  3b 
  3  1700xxc3  3c 
  4  1700xxc4  3a 
  5  1800xxc5  3a 
  6  1800xxc6  3a 
  7  1800xxc7  3b 

the query

SELECT 
    t1.DOC,
    t1.TYPE,
    COUNT(*) AS [Ino Seq]
FROM 
    MyData AS t1
    INNER JOIN
    MyData AS t2
        ON t2.DOC = t1.DOC
            AND t2.Ino <= t1.Ino
GROUP BY
    t1.DOC,
    t1.TYPE
ORDER BY 1, 3

returns

DOC  TYPE      Ino Seq
---  --------  -------
3a   1800xxc1        1
3a   1700xxc4        2
3a   1800xxc5        3
3a   1800xxc6        4
3b   1810xxc2        1
3b   1800xxc7        2
3c   1700xxc3        1