Python: string is escaped when creating a tuple

问题

I have the following code:

string = "ad\23e\4x{\s"
data = (string,)

When I print the data my string in the tuple has an extra slash for each slash a total of 6 back slashes.

How can I avoid the extra back slashes?

回答1:

The object data is a tuple. When you print a tuple, Python call repr for each element. If you want to format it another way, you have to do the conversion yourself.

>>> s = "ad\23e\4x{\s"
>>> d = (s,)
>>> print d
('ad\x13e\x04{\\s',)
>>> print '(%s,)' % (', '.join('"%s"' % _ for _ in d))
("adex{\s")

回答2:

Those extra backslashes aren't actually in your string, they are just how Python represents strings (the idea being that you could paste that back into a program and it would work). It's doing that because the tuple's __str__() implementation calls repr() on each item. If you print string or print data[0] you will see what's actually in the string.

回答3:

You mean something like this?

In [11]: string = r'ad\23e\4x{\s'

In [12]: string
Out[12]: 'ad\\23e\\4x{\\s'

In [13]: print string
ad\23e\4x{\s

In [14]: data=(string,)

In [15]: data
Out[15]: ('ad\\23e\\4x{\\s',)

In [16]: print data
('ad\\23e\\4x{\\s',)

In [17]: print data[0]
ad\23e\4x{\s

来源：https://stackoverflow.com/questions/7145934/python-string-is-escaped-when-creating-a-tuple