How do I combine three observables such that

问题

If I have three observables, how do I combine them such that when the first emit a new value, I can combine that with the latest emitted from the other two.. Its important that we only produce a new value of the combined observables when the first observable has a new value regardles of whether the other two has emitted new values.

Thanks.

回答1:

You could do this (note that you get default values for sources 2 and 3 if they have yet to emit, and I have allowed for you to optionally supply those default values):

public static class ObservableExtensions
{
    public static IObservable<TResult> CombineFirstWithLatestOfRest
        <TSource1, TSource2, TSource3, TResult>(
        this IObservable<TSource1> source1,
        IObservable<TSource2> source2,
        IObservable<TSource3> source3,
        Func<TSource1, TSource2, TSource3, TResult> resultSelector,
        TSource2 source2Default = default(TSource2),
        TSource3 source3Default = default(TSource3))
    {
        var latestOfRest = source2.CombineLatest(source3, Tuple.Create);
        return source1.Zip(latestOfRest.MostRecent(
            Tuple.Create(source2Default, source3Default)),
            (s1,s23) => resultSelector(s1, s23.Item1, s23.Item2));
    }
}

Example use:

var source1 = Observable.Interval(TimeSpan.FromSeconds(2));
var source2 = Observable.Interval(TimeSpan.FromSeconds(1));
var source3 = Observable.Interval(TimeSpan.FromSeconds(3.5));

var res = source1.CombineFirstWithLatestOfRest(source2, source3,
    (x,y,z) => string.Format("1: {0} 2: {1} 3: {2}", x,y,z));    

res.Subscribe(Console.WriteLine);

Addendum

There's a subtle problem here that might be significant in your scenario. A sometimes undesirable aspect of CombineLatest is that it does not emit until it has a value from every contributing stream. This means in the example above that the slower source3 holds up source2 and values are missed. Specifically, events returned will have the default values for both source2 and source3 until both have emitted at least one event each. Kicking off source2 and source3 with their default values is a convenient workaround for this behaviour, which we can get away with since it is source1 that drives events:

public static class ObservableExtensions
{
    public static IObservable<TResult> CombineFirstWithLatestOfRest
        <TSource1, TSource2, TSource3, TResult>(
        this IObservable<TSource1> source1,
        IObservable<TSource2> source2,
        IObservable<TSource3> source3,
        Func<TSource1, TSource2, TSource3, TResult> resultSelector,
        TSource2 source2Default = default(TSource2),
        TSource3 source3Default = default(TSource3))
    {   
        source2 = source2.StartWith(source2Default); // added this
        source3 = source3.StartWith(source3Default); // and this           
        var lastestOfRest = source2.CombineLatest(source3, Tuple.Create);            
        return source1.Zip(lastestOfRest.MostRecent(
            Tuple.Create(source2Default, source3Default)), // now redundant
            (s1,s23) => resultSelector(s1, s23.Item1, s23.Item2));
    }             
}

来源：https://stackoverflow.com/questions/27422994/how-do-i-combine-three-observables-such-that

标签

system.reactive