问题
I have this base class having the following interface:
abstract class Base
{
abstract public object Val
{
get;
}
}
For any derived classes, Val
's value must be specified at object creation time.
The question is: How can I make a derived class do this (hopefully at compile time)?
I tried adding a constructor:
abstract class Base
{
public Base(object value)
{
val = value;
}
private object val;
...
}
But as you can see then I had to declare a private field to store value in it (because Value is read-only).
The problem arises because I want to add some kind of effect to derived classes using the Decorator/Wrapper pattern introduced in GoF Design Patterns. But because I have declared the field inside Base class, the decorators keep saving a copy of the same data and I end up wasting memory.
回答1:
Try this instead:
abstract class Base
{
public Base(object val)
{
this.Val = val;
}
public object Val { get; private set; }
}
That way, your derived class doesn't need its own field:
public class Derived : Base
{
public Derived(object val) : base(val) { }
}
回答2:
If it is a decorator, then don't have a field:
public override object Val {
// add any decoration effects here if needed
get { return tail.Val; }
}
Where tail
is the thing you are decorating.
However, it sounds like you mean inheritance (not decoration) - if so:
abstract class BaseClass {
protected BaseClass(object val) {...}
}
class ConcreteType : BaseClass {
public ConcreteType(object val)
: base(val) { }
}
Here the base class could even handle the storage etc.
来源:https://stackoverflow.com/questions/8466706/decorator-pattern-wasting-memory