问题
How do I find out the length or the number of digits of the fraction part of a decimal number?
I can see a few aproaches, e.g. with Strings like this one:
public static int getNumberOfFractionDigits(Number number) {
Double fractionPart = number.doubleValue() - number.longValue();
return fractionPart.toString().length() - 2;
}
But what is the best way to determine the length?
I could imagine some problems if I use Strings, e.g. because the locale and number format may be different from system to system. Is there a nice way to calculate it? Maybe without iteration?
Thanks in advance.
回答1:
I just wrote a simple method for this, hope it can help someone.
public static int getFractionDigitsCount(double d) {
if (d >= 1) { //we only need the fraction digits
d = d - (long) d;
}
if (d == 0) { //nothing to count
return 0;
}
d *= 10; //shifts 1 digit to left
int count = 1;
while (d - (long) d != 0) { //keeps shifting until there are no more fractions
d *= 10;
count++;
}
return count;
}
回答2:
You may use java.text.NumberFormat.
nf = java.text.NumberFormat.getInstance ();
// without BigDecimal, you will reach the limit far before 100
nf.setMaximumFractionDigits (100);
String s = nf.format (number.doubleValue ())
You may set the Decimal-Identifier as you like, and use regular expressions to cut off the leading part, and String.length () to evaluate the rest.
回答3:
Try this:
public static int getNumberOfFractionDigits(Number number) {
if( number == null ) return 0; //or throw
if( number.doubleValue() == 0.0d ) return 0;
BigDecimal bd = new BigDecimal(number.toString());
//BigDecimal bd = BigDecimal.valueOf(number.doubleValue()); // if double precision is ok, just note that you should use BigDecimal.valueOf(double) rather than new BigDecimal(double) due to precision bugs in the latter
bd = bd.stripTrailingZeros(); //convert 1.00 to 1 -> scale will now be 0, except for 0.0 where this doesn't work
return bd.scale();
}
Edit:
If the number is actually an iteger (i.e. fraction of 0) this would still return 1. Thus you might check whether there actually is a fractional part first.
Edit2:
stripTrailingZeros()
seems to do the trick, except for 0.0d. Updated the code accordingly.
回答4:
Looks like many offered the Big Decimal. It's easy on the eyes at least. The code shall work for ya.
package t1;
import java.math.*;
public class ScaleZ {
private static final int MAX_PRECISION = 10;
private static final MathContext mc = new MathContext(MAX_PRECISION, RoundingMode.HALF_EVEN);
public static int getScale(double v){
if (v!=v || v == Double.POSITIVE_INFINITY || v == Double.NEGATIVE_INFINITY)
return 0;//throw exception or return any other stuff
BigDecimal d = new BigDecimal(v, mc);
return Math.max(0, d.stripTrailingZeros().scale());
}
public static void main(String[] args) {
test(0.0);
test(1000d);
test(1d/3);
test(Math.PI);
test(1.244e7);
test(1e11);
}
private static void test(double d) {
System.out.printf("%20s digits %d%n", d, getScale(d));
}
}
回答5:
That was my best implementation:
public class NumberHandler {
private static NumberFormat formatter = NumberFormat.getInstance(Locale.ENGLISH);
static {
formatter.setMaximumFractionDigits(Integer.MAX_VALUE);
formatter.setGroupingUsed(false);
}
public static int getFractionLength(double doubleNumber) {
String numberStr = formatter.format(doubleNumber);
int dotIndex = numberStr.indexOf(".");
if (dotIndex < 0) {
return 0;
} else {
return numberStr.length() - (dotIndex + 1);
}
}
}
Not effective, probably not perfect, but the other options was worse.
回答6:
public static int getNumberOfFractionDigits(double d) {
String s = Double.toString(d), afterDecimal="";
afterDecimal = s.subString(s.indexOf(".") + 1, s.length() - 1);
return afterDecimal.length();
}
来源:https://stackoverflow.com/questions/5314954/how-to-get-the-length-of-a-numbers-fraction-part