Conditional Statement on Java7

问题

Hello i just started a coding exercise on hackerrank and i am having a little challenge using scanner class with the skip function. here is what i have tried. Objective In this challenge, we're getting started with conditional statements. Check out the Tutorial tab for learning materials and an instructional video!

Task

Given an integer, perform the following conditional actions:

If n is odd, print Weird
If n is even and in the inclusive range of 2 to 5, print Not Weird
If n is even and in the inclusive range of 6 to 20, print Weird
If n is even and greater than 20, print Not Weird
Complete the stub code provided in your editor to print whether or not n is weird.

Input Format

A single line containing a positive integer,n.

Constraints

Output Format

Print Weird if the number is weird; otherwise, print Not Weird.

import java.io.*;
import java.math.*;
import java.security.*;
import java.text.*;
import java.util.*;
import java.util.concurrent.*;
import java.util.regex.*;

public class Solution {


    private static final Scanner scanner = new Scanner(System.in);

    public static void main(String[] args) {
        int N = scanner.nextInt();

        if (N % 2 == 0 && N >= 2 && N <= 5 && N > 20) {
            System.out.println("not weird");

        } else if (N % 2 == 0 && N >= 6 && N <= 20) {
            System.out.println("weird");
        } else {
            System.out.println("weird");
        }

        scanner.skip("(\r\n|[\n\r\u2028\u2029\u0085])?");


        scanner.close();
    }
}

Please what am i doing wrong.

回答1:

You're mixing up && and ||, so your first if will never run as mentioned in the comments.

So it looks like the only "Not Weird" print out is 2, 4 and even numbers > 20.

So use this to your advantage to just check for the "Weird" outputs, otherwise print "Not Weird".

if (n % 2 == 0) {
    if ((n >= 2 && n <= 5) || (n > 20)) {
        return "Not Weird";
    }
}
return "Weird";

Online Demo

Having said this, I'm not sure what you want with Scanner::skip

回答2:

This is how I simplified it.

    if(N % 2 == 0 )
    {            
        if((N >= 2 && N <= 5) || N > 20)
        {
            System.out.println("Not Weird");
        }
        else
        {
            System.out.println("Weird");
        }    
    }
    else
    {
        System.out.println("Weird");
    }

回答3:

See code below

int N = scanner.nextInt();
scanner.skip("(\r\n|[\n\r\u2028\u2029\u0085])?");

if ((N % 2 == 0 && N >= 2 && N <= 5) || N > 20) {
    System.out.println("Not Weird");

} else if (N % 2 == 0 && N >= 6 && N <= 20) {
    System.out.println("Weird");
} 
else 
{
    System.out.println("Weird");
}

来源：https://stackoverflow.com/questions/52645699/conditional-statement-on-java7

标签

java

if-statement

java.util.scanner