Why Size is different for different pointers

问题

#include <stdio.h>

#define R 10
#define C 20

int main()
{
    int *p;
    int *p1[R];
    int *p2[R][C];
    printf("%d %d %d", sizeof(*p),sizeof(*p1),sizeof(*p2));
    getchar();
    return 0;
}

Why is the output: 4 8 160? Why does size of p1 becomes 8 and not 4?

回答1:

Consider the types.

1. sizeof(*p) ==> sizeof(int)
2. sizeof(*p1) ==> sizeof(int *)
3. sizeof(*p2) ==> sizeof((int [20]))

Note: Depending on your platform and compiler, you'll get different results.

Also, as we know, sizeof produces a result of type size_t, it's advised to use %zu format specifier to print the result.

来源：https://stackoverflow.com/questions/31556285/why-size-is-different-for-different-pointers