问题
I am on 64-bit Linux x86. I need to execute mmap
syscall using syscall
function. mmap
syscall number is 9:
printf("mmap-1: %lli\n", syscall(9, 0, 10, 3, 2 | 32, -1, 0));
printf("mmap-2: %lli\n", mmap( 0, 10, 3, 2 | 32, -1, 0));
However, when I run it, the syscall
function gives wrong results.
mmap-1: 2236940288
mmap-2: 140503502090240
mmap-1: 3425849344
mmap-2: 140612065181696
mmap-1: 249544704
mmap-2: 139625341366272
mmap
works just fine, but the "addresses" returned syscall
result in Segmentation fault
. The values from syscall
seem to be cast to 32 bits or something.
What am I doing wrong?
回答1:
In your syscall()
, instead of passing in 0 (NULL)
for the first parameter, addr
, pass some pointer you have declared previously. This way you can access the memory mapped by mmap
. mmap
function declaration:
void *mmap(void *addr, size_t length, int prot, int flags, int fd, off_t offset);
回答2:
Found the cause of the problem: I was running gcc
with -std=c99
option, removing it solved the problem:
mmap-1: 139975263928320
mmap-2: 139975263924224
I guess, -std=99
defines syscall as int syscall()
and without it its long syscall()
.
来源:https://stackoverflow.com/questions/38640828/c-syscall-64-bit-pointer