问题
Basically Im trying to make a program that allows a teacher to input grades for a test for each student then after they've inputted the grades it gives the teacher a sum of all the grades they inputted
public static void grades(){
List<Integer> grade = new ArrayList<Integer>();
int gradetotal = IntStream.of(grades).sum;/* sum */
int gradelistnumber = 1;
int inputedgrade = 0;
while(inputedgrade != -1){
System.out.println("Enter Grade for student " + gradelistnumber + " (1-50): ");
inputedgrade = sc.nextInt();
grade.add(inputedgrade);
gradelistnumber++;
}
System.out.println("Class Average: " + gradetotal / 50 * 100);
}
I'm trying to figure out how to get the sum of the array list grades .
回答1:
Here's how you sum a Collection using java 8:
import java.util.ArrayList;
import java.util.List;
public class Solution {
public static void main(String args[]) throws Exception {
List<Integer> numbers = new ArrayList<>();
numbers.add(1);
numbers.add(3);
numbers.add(5);
System.out.println(numbers.stream().mapToInt(value -> value).sum());
}
}
In your code, you would do this to the grade
list. You can set this to gradetotal
after your loop.
value -> value
is saying "take each argument and return it". stream()
returns a Stream
which doesn't have sum()
. mapToInt
returns an IntStream
which does have sum()
. That value -> value
tells the code how to convert each element in the Stream
into an Integer
. Because each element is already an Integer
, we merely have to return each element.
回答2:
Instead of maintaining an array, why not just keep two temporary variables - a count and a summation?
int gradetotal = 0;
int gradelistnumber = 0;
int inputedgrade = 0;
while(inputedgrade != -1){
System.out.println("Enter Grade for student " + gradelistnumber + " (1-50): ");
inputedgrade = sc.nextInt();
gradetotal = gradetotal + inputedgrade;
gradelistnumber++;
}
来源:https://stackoverflow.com/questions/26242176/how-to-get-the-sum-of-an-integer-arraylist