item in a list of a list is not beeing displayed [closed]

问题

it shows me the idfichier, and the nomclient shows system.linq.enumerable... I guess it is showing the type of nomclient.

public static void generateCTAF(string pathXml, string outputPDF)
        {
            List<FichierCTAF> fc = new List<FichierCTAF>();

            fc = getXmlFCtaf(pathXml);

            foreach (FichierCTAF f in fc)
            {
                Console.WriteLine("ID CTAF : {0} \n Nom Client : {1}\n \n", f.IdFichierCtaf, f.Clients.Select(y => y.NomClient ));
            }

        }

How can I display that? the picture displays the result that i got

回答1:

You see that strange System.Linq.Enumerable+WhereSelectListIterator because it's ToString() representation of list iterator, which is returned by f.Clients.Select(y => y.NomClient) query.

If you need to display all NomClient values, I suggest you to build concatenated string of them:

public static void generateCTAF(string pathXml, string outputPDF)
{
    List<FichierCTAF> fc = getXmlFCtaf(pathXml);

    foreach (FichierCTAF f in fc)
    {
        Console.WriteLine("ID CTAF : {0}\n Nom Client : {1}\n\n", 
           f.IdFichierCtaf, 
           String.Join(", ", f.Clients.Select(y => y.NomClient)));
    }
}

Or you can enumerate NomClients values and print each on its own line:

public static void generateCTAF(string pathXml, string outputPDF)
{
    List<FichierCTAF> fc = getXmlFCtaf(pathXml);

    foreach (FichierCTAF f in fc)
    {
        Console.WriteLine("ID CTAF : {0}", f.IdFichierCtaf);

        foreach(string nomClient in f.Clients.Select(y => y.NomClient))
            Console.WriteLine(" Nom Client : {0}", nomClient);
    }
}

回答2:

Rather than using SelectMany use Select

f.Clients.Select(y => y.NomClient)

Update:

I got your problem. If you use Select then it returns IEnumberable<String> so you need iterate to print the values of NomClient.

Currently you are not looping to print multiple values, below is the example to print values in comma separated.

String.Join(", ", f.Clients.Select(y => y.NomClient))

Use below line:

Console.WriteLine("ID CTAF : {0} \n Nom Client : {1}\n \n", f.IdFichierCtaf, String.Join(", ", f.Clients.Select(y => y.NomClient)));

来源：https://stackoverflow.com/questions/21306482/item-in-a-list-of-a-list-is-not-beeing-displayed

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