问题
I am trying to create a number guessing game with multiple numbers. The computer generates 4 random numbers between 1 and 9 and then the user has 10 chances to guess the correct numbers. I need the feedback to display as YYYY
for 4 correct numbers guessed, YNNY
for first and last number guessed etc. (you get the point). the code below keeps coming back saying IndexError: list index out of range
.
from random import randint
guessesTaken = 0
randomNumber = []
for x in range(4):
tempNumber = randint(1, 9)
randomNumber.append(tempNumber)
Guess = []
Guess.append(list(input("Guess Number: ")))
print(randomNumber)
print(Guess)
if randomNumber[0] == Guess[0]:
print("Y")
elif randomNumber[1] == Guess[1]:
print("Y")
elif randomNumber[2] == Guess[2]:
print("Y")
elif randomNumber[3] == Guess[3]:
print("Y")
elif randomNumber[0] != Guess[0]:
print("N")
elif randomNumber[1] != Guess[1]:
print("N")
elif randomNumber[2] != Guess[2]:
print("N")
elif randomNumber[3] != Guess[3]:
print("N")
回答1:
You need four guesses to match for random numbers, you can also shorted your code using a list comp:
from random import randint
guessesTaken = 0
randomNumber = []
Guess = []
for x in range(4):
tempNumber = str(randint(1, 9)) # compare string to string
randomNumber.append(tempNumber)
Guess.append(input("Guess Number: "))
print("".join(["Y" if a==b else "N" for a,b in zip(Guess,randomNumber)]))
You can also use enumerate to check elements at matching indexes:
print("".join(["Y" if randomNumber[ind]==ele else "N" for ind, ele in enumerate(Guess)]))
To give the user guesses in a loop:
from random import randint
guessesTaken = 0
randomNumber = [str(randint(1, 9)) for _ in range(4)] # create list of random nums
while guessesTaken < 10:
guesses = list(raw_input("Guess Number: ")) # create list of four digits
check = "".join(["Y" if a==b else "N" for a,b in zip(guesses,randomNumber)])
if check == "YYYY": # if check has four Y's we have a correct guess
print("Congratulations, you are correct")
break
else:
guessesTaken += 1 # else increment guess count and ask again
print(check)
回答2:
Right now you're only asking the user for one guess, and appending the guess to the Guess
list. So the Guess
list has one element, but you're using Guess[1]
, Guess[2]
, etc., which of course results in the IndexError
回答3:
I'll rearrange your code a bit, so it doesn't stray too far from what you've done.
from random import randint
guessesTaken = 0
randomNumbers = []
Guess = [] # Combine your guesses with your loop
for x in range(4):
tempNumber = randint(1, 9)
randomNumbers.append(tempNumber)
# This should be done four times too
# In Python 2, instead of this:
# Guess.append(input("Guess Number: "))
# do this:
Guess.append(int(raw_input("Guess Number: "))) # raw_input and pass to int
# in python 3, raw_input becomes input, so do this instead:
# Guess.append(int(input("Guess Number: ")))
print(randomNumbers)
print(Guess)
You can combine these in a loop to avoid the repetitive code:
if randomNumbers[0] == Guess[0]:
print("Y")
else:
print("N")
if randomNumbers[1] == Guess[1]:
print("Y")
else:
print("N")
if randomNumbers[2] == Guess[2]:
print("Y")
else:
print("N")
if randomNumbers[3] == Guess[3]:
print("Y")
else:
print("N")
Perhaps, to print your desired result e.g. YNNY, like this:
result = []
for index in range(4):
if randomNumbers[index] == Guess[index]:
result.append("Y")
else:
result.append("N")
print(''.join(result))
If you want terser code use Python's ternary operation:
result = []
for index in range(4):
result.append("Y" if randomNumbers[index] == Guess[index] else "N")
print(''.join(result))
Or use the fact that True == 1
and False == 0
as indexes:
result = []
for index in range(4):
result.append("NY"[randomNumbers[index] == Guess[index]])
print(''.join(result))
来源:https://stackoverflow.com/questions/26557773/python-multiple-number-guessing-game