Why does this Kotlin method have enclosing backticks?

限于喜欢 提交于 2019-11-27 04:57:58

It's because is is a reserved keyword in Kotlin. Since Kotlin is supposed to be interoperable with Java and is is a valid method (identifier) name in Java, the backticks are used to escape the method so that it can be used as a method without confusing it as a keyword. Without it it will not work because it would be invalid syntax.

This is highlighted in the Kotlin documentation:

Escaping for Java identifiers that are keywords in Kotlin

Some of the Kotlin keywords are valid identifiers in Java: in, object, is, etc. If a Java library uses a Kotlin keyword for a method, you can still call the method escaping it with the backtick (`) character

foo.`is`(bar)

It allows you to call a Java method whose name is a Kotlin keyword. It won't work if you leave out the backticks.

The backtick are a "workaround" to allow you to call methods that have a name representing a Kotlin keyword.

See kotlinlang:

Some of the Kotlin keywords are valid identifiers in Java: in, object, is, etc. If a Java library uses a Kotlin keyword for a method, you can still call the method escaping it with the backtick (`) character

is in list of Kotlin reserved words To use Kotlin reserved word (such as is or object) for function/class name you should wrap it to backticks

Some of the Kotlin keywords are valid identifiers in Java: in, object, is, etc. If a Java library uses a Kotlin keyword for a method, you can still call the method escaping it with the backtick (`) character

https://kotlinlang.org/docs/reference/java-interop.html

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