MATLAB eig returns inverted signs sometimes

杀马特。学长 韩版系。学妹 提交于 2019-11-27 04:55:26

Note that eigenvectors are not unique. Multiplying by any constant, including -1 (which simply changes the sign), gives another valid eigenvector. This is clear given the definition of an eigenvector:

A·v = λ·v

MATLAB chooses to normalize the eigenvectors to have a norm of 1.0, the sign is arbitrary:

For eig(A), the eigenvectors are scaled so that the norm of each is 1.0. For eig(A,B), eig(A,'nobalance'), and eig(A,B,flag), the eigenvectors are not normalized

Now as you know, SVD and eigendecomposition are related. Below is some code to test this fact. Note that svd and eig return results in different order (one sorted high to low, the other in reverse):

% some random matrix
A = rand(5);

% singular value decomposition
[U,S,V] = svd(A);

% eigenvectors of A'*A are the same as the right-singular vectors
[V2,D2] = eig(A'*A);
[D2,ord] = sort(diag(D2), 'descend');
S2 = diag(sqrt(D2));
V2 = V2(:,ord);

% eigenvectors of A*A' are the same as the left-singular vectors
[U2,D2] = eig(A*A');
[D2,ord] = sort(diag(D2), 'descend');
S3 = diag(sqrt(D2));
U2 = U2(:,ord);

% check results
A
U*S*V'
U2*S2*V2'

I get very similar results (ignoring minor floating-point errors):

>> norm(A - U*S*V')
ans =
   7.5771e-16
>> norm(A - U2*S2*V2')
ans =
   3.2841e-14

EDIT:

To get consistent results, one usually adopts a convention of requiring that the first element in each eigenvector be of a certain sign. That way if you get an eigenvector that does not follow this rule, you multiply it by -1 to flip the sign...

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