How to satisfy or bypass viewstate validation in Asp.net WebForms on separate post?

问题

I`ve got a link in a Webforms page which opens in a new window, and posts to a form other than the page itself. This is done like this:

JS:

var submitFunc = function(){
    document.forms[0].action = 'http://urlToPostTo/somePage.aspx';  
    document.forms[0].target = '_blank'; 
    document.forms[0].submit();
}

The link:

<input type="hidden" id="myDataId" value="12345" />     
<a href="javascript:submitFunc();">Search</a>

As you can see, this overrides the target of the main <form>, and attempts to post to a different page. The whole point is that this should post/submit to a different page, while avoiding passing the data of "myDataId" as a Get parameter.

The above code would work, but causes an error due to viewstate validation.

Question: Is there any way for me to either satisfy the requirements here, or somehow bypass the viewstate validation so I can post my data this way?

回答1:

Sounds like you just need to change the PostBackUrl of the button that submits the form.

A simple example PostToPage1.aspx that posts to PostToPage2.aspx (instead of a postback):

<form id="form1" runat="server">
<div>
    <asp:TextBox ID="text1" runat="server" /><br />
    <asp:TextBox ID="text2" runat="server" />
    <asp:Button ID="btn1" runat="server" PostBackUrl="~/PostToPage2.aspx" />
</div>
</form>

You can then inspect the Request in PostToPage2.aspx to check if it's a POST, etc. and then access the Request.Form collection in the Request in Page_Load.

An overly simplified sample for PostToPage2.aspx (do add proper validation):

if (!Page.IsPostBack && Request.RequestType == "POST")
    {
        if (Request.Form != null && Request.Form.Keys.Count > 0)
        {
           .....

Hth...

来源：https://stackoverflow.com/questions/12690214/how-to-satisfy-or-bypass-viewstate-validation-in-asp-net-webforms-on-separate-po

标签

javascript

ASP.NET

validation

webforms

viewstate