Want to know the ESSID of wireless network via C++ in UBUNTU

问题

I have written the following program to get the ESSID of the wireless network to which my Desktop is currently connected, but it is giving me errors. Can anyone help me correct the bugs? Code:

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <sys/ioctl.h>
#include <sys/stat.h>
#include <sys/socket.h>
#include <sys/types.h> 
#include <fcntl.h>
#include <errno.h>
#include <linux/wireless.h>

#define IW_INTERFACE "wlan0"

extern int errno;
struct iwreq wreq;

int main (void)
{
    int sockfd;
    char * id;

    memset(&wreq, 0, sizeof(struct iwreq));
    sprintf(wreq.ifr_name, IW_INTERFACE);

    if((sockfd = socket(AF_INET, SOCK_DGRAM, 0)) == -1) {
        fprintf(stderr, "Cannot open socket \n");
        fprintf(stderr, "errno = %d \n", errno);
        fprintf(stderr, "Error description is : %s\n",strerror(errno));
        exit(1);
    }
    printf("Socket opened successfully \n");


    id = new char(IW_ESSID_MAX_SIZE+1);
    wreq.u.essid.pointer = id;
    if (ioctl(sockfd,SIOCGIWESSID, &wreq) == -1) {
        fprintf(stderr, "Get ESSID ioctl failed \n");
        fprintf(stderr, "errno = %d \n", errno);
        fprintf(stderr, "Error description : %s\n",strerror(errno));
        exit(2);
    }
    printf("IOCTL Successfull\n");
    printf("ESSID is %s\n", wreq.u.essid.pointer);
    exit(0);
}

I am getting following error:

  > 1. Get ESSID ioctl failed 
  > 2. errno = 7 
  > 3. Error description : Argument list too long

回答1:

You should set length properly first before using werq, check this,

int sockfd;
    char * id;
   id = new char[IW_ESSID_MAX_SIZE+1];

    struct iwreq wreq;
    memset(&wreq, 0, sizeof(struct iwreq));
    wreq.u.essid.length = IW_ESSID_MAX_SIZE+1;

    sprintf(wreq.ifr_name, IW_INTERFACE);

    if((sockfd = socket(AF_INET, SOCK_DGRAM, 0)) == -1) {
        fprintf(stderr, "Cannot open socket \n");
        fprintf(stderr, "errno = %d \n", errno);
        fprintf(stderr, "Error description is : %s\n",strerror(errno));
        exit(1);
    }
    printf("\nSocket opened successfully \n");

    wreq.u.essid.pointer = id;
    if (ioctl(sockfd,SIOCGIWESSID, &wreq) == -1) {
        fprintf(stderr, "Get ESSID ioctl failed \n");
        fprintf(stderr, "errno = %d \n", errno);
        fprintf(stderr, "Error description : %s\n",strerror(errno));
        exit(2);
    }

    printf("IOCTL Successfull\n");

    printf("ESSID is %s\n", (char *)wreq.u.essid.pointer);

回答2:

You are testing the return code of ioctl(2) incorrectly. ioctl(2) returns -1 on error, not true (non-zero). Since an error is not being returned, the value in errno is undefined and is misleading.

It should read:

if (ioctl(sockfd,SIOCGIWESSID, &wreq) == -1) {
    fprintf(stderr, "Get ESSID ioctl failed \n");
    fprintf(stderr, "errno = %d \n", errno);
    fprintf(stderr, "Error description : %s\n",strerror(errno));
    exit(2);
}

Edit: With that incorrect code out of the way, there's this:

id = new char(IW_ESSID_MAX_SIZE+1);

Perhaps you meant:

id = new char[IW_ESSID_MAX_SIZE+1];

The former allocated only a single character and sets its value to IW_ESSID_MAX_SIZE+1. The latter allocates an array of size IW_ESSID_MAX_SIZE+1.

With that change, the code works for me and does not give an error for the ioctl.

回答3:

Try setting wreq.u.essid.length to the right value.

回答4:

printf("Socket opened successfully \n");

//id = new char(IW_ESSID_MAX_SIZE+1);
char buffer[32];
memset(buffer, 0, 32);
wreq.u.essid.pointer = buffer;
wreq.u.essid.length = 32;

//wreq.u.essid.pointer = id;
if (ioctl(sockfd,SIOCGIWESSID, &wreq) == -1) {
    fprintf(stderr, "Get ESSID ioctl failed \n");
    fprintf(stderr, "errno = %d \n", errno);
    fprintf(stderr, "Error description : %s\n",strerror(errno));
    exit(2);
}
printf("IOCTL Successfull\n");

来源：https://stackoverflow.com/questions/5937757/want-to-know-the-essid-of-wireless-network-via-c-in-ubuntu

标签

Ubuntu

wireless