问题
I've written a directive that dynamically creates a popover for an element:
app.directive('popover', function($compile, $timeout){
return {
link: function(scope, element, attrs) {
$timeout(function() {
// grab template
var tpl = $(element).find('.popover-template')
// grab popover parts of template
var template = {
//$compile( $(element).siblings(".pop-content").contents() )(scope)
title: tpl.find('.template-title').contents(),
content: tpl.find('.template-content').contents()
};
// render template with angular
var content = $compile(template.content)(scope);
var title = $compile(template.title)(scope);
$(element).popover({
html: true,
placement: "right",
content: content,
title: title
});
scope.$digest()
});
}
};
});
In application it looks like this:
<span popover>Click me</span>
<div ng-hide="true" class="popover-template">
<div class="template-title">
<strong>{{ x.name }} and {{ y.name }}</strong>
</div>
<div class="template-content">
<div>
<pre>f in [1,2,3]</pre>
<div ng-repeat="f in [1,2,3]">
item {{ f }}, index {{ $index }}
</div>
</div>
</div>
</div>
The popover is created and displayed. The title works correctly as well. However, ng-repeat is applied multiple times in any iteration:

As you can see, the iteration that should only include 3 elements in fact includes 3*3 elements. The directive creates popovers for exactly 3 elements, so I guess that's where my mistake lies. How can I make sure that within each popover, ng-repeat
is only called once?
回答1:
The problem
Since the popover-template element is already in the document when you bootstrapped the angular application (at page load), it has already been compiled once. The ng-repeat element is replaced with 3 new elements:
<!-- original -->
<div ng-repeat="f in [1,2,3]">item {{ f }}, index {{ $index }}</div>
<!-- replaced -->
<div ng-repeat="f in [1,2,3]">item 1, index 0</div>
<div ng-repeat="f in [1,2,3]">item 2, index 1</div>
<div ng-repeat="f in [1,2,3]">item 3, index 2</div>
When you compile it again in the link function, each of the 3 ng-repeats is triggered, making 3 identical copies, 9 total.
The solution
Keep your popover-template in a separate file so it is not compiled on page load. You can then load it with the $templateCache service.
In general, just make sure you don't compile your HTML multiple times.
回答2:
Instead using the compiled html for the popover template, load the template using $http or templateCache.
The HTML:
<span popover>Click me</span>
<script type="text/ng-template" id="popover.html">
<div class="popover-template">
<div class="template-title">
<strong>{{ x.name }} and {{ y.name }}</strong>
</div>
<div class="template-content">
<div>
<pre>f in [1,2,3] track by $index</pre>
<div ng-repeat="f in [1,2,3]">
item {{ f }}, index {{ $index }}
</div>
</div>
</div>
</div>
</script>
The Javascript:
angular.module('app',[]).directive('popover', function($compile, $timeout, $templateCache){
return {
link: function(scope, element, attrs) {
$timeout(function() {
// grab the template (this is the catch)
// you can pass the template name as a binding if you want to be loaded dynamically
var tpl = angular.element($templateCache.get('popover.html'));
// grab popover parts of template
var template = {
title: tpl.find('.template-title').contents(),
content: tpl.find('.template-content').contents()
};
// render template with angular
var content = $compile(template.content)(scope);
var title = $compile(template.title)(scope);
$(element).popover({
html: true,
placement: "right",
content: content,
title: title
});
scope.$digest()
});
}
};
});
Also, I have made this plunker with an working example: http://embed.plnkr.co/IoIG1Y1DT8RO4tQydXnX/
来源:https://stackoverflow.com/questions/26578446/angularjs-ng-repeat-applied-multiple-times-in-compiled-directive