问题
I have a String "Saturday, Oct, 25th, 11:40"
What format does this date has? How can I parse the ordinal indicator?
Here is how i want to convert it
private String changeDateFormat(String stringDate){
DateFormat dateFormat = new SimpleDateFormat("DD, MM, ddth, hh:mm");
try {
Date date = dateFormat.parse(stringDate);
dateFormat = new SimpleDateFormat("ddMMMyyyy");
stringDate=dateFormat.format(date);
} catch (ParseException e) {
e.printStackTrace();
}
return stringDate.toUpperCase();
}
回答1:
SimpleDateFormat
doesn't seem to easily handle day numbers followed by "st" "th" etc. A simple solution would be remove that part of the original string. E.g.
int comma = original.lastIndexOf(',');
String stringDate =
original.substring(0, comma - 2) +
original.substring(comma + 1);
After that just use this format on stringDate
:
SimpleDateFormat("EE, MM, dd, hh:mm")
回答2:
Hope this program solve your problem.
public class Test
{
public static void main(String[] args) {
System.out.println(new Test().getCurrentDateInSpecificFormat(Calendar.getInstance()));
}
private String getCurrentDateInSpecificFormat(Calendar currentCalDate) {
String dayNumberSuffix = getDayNumberSuffix(currentCalDate.get(Calendar.DAY_OF_MONTH));
DateFormat dateFormat = new SimpleDateFormat("E, MMM, dd'"+ dayNumberSuffix +"', HH:mm");
return dateFormat.format(currentCalDate.getTime());
}
private String getDayNumberSuffix(int day) {
if (day >= 11 && day <= 13) {
return "th";
}
switch (day % 10) {
case 1:
return "st";
case 2:
return "nd";
case 3:
return "rd";
default:
return "th";
}
}
}
回答3:
The java doc has lot of information on how to parse a date from String in different formats :
SimpleDateFormat Java Doc
You can try with this, but play around this and refer java doc until you are able to solve your problem :
DateFormat dateFormat = new SimpleDateFormat("E, MMM, dd'th' HH:mm");
Date date = dateFormat.parse("Saturday, Oct, 25th, 11:40");
Try different combinations, that way you will learn more about SimpleDateFormat and how it works with different formats.
回答4:
One solution would be to parse the parameter in order to know which pattern to use:
private String changeDateFormat(String stringDate) {
DateFormat dateFormat;
if (stringDate.matches("^([a-zA-Z]+, ){2}[0-9]+st, [0-9]{2}:[0-9]+{2}")) {
dateFormat = new SimpleDateFormat("E, MMM, dd'st', HH:mm");
} else if (stringDate.matches("^([a-zA-Z]+, ){2}[0-9]+nd, [0-9]{2}:[0-9]+{2}")) {
dateFormat = new SimpleDateFormat("E, MMM, dd'nd', HH:mm");
} else if (stringDate.matches("^([a-zA-Z]+, ){2}[0-9]+rd, [0-9]{2}:[0-9]+{2}")) {
dateFormat = new SimpleDateFormat("E, MMM, dd'rd', HH:mm");
} else {
dateFormat = new SimpleDateFormat("E, MMM, dd'th', HH:mm");
}
try {
Date date = dateFormat.parse(stringDate);
dateFormat = new SimpleDateFormat("ddMMMyyyy");
stringDate = dateFormat.format(date);
} catch (ParseException e) {
e.printStackTrace();
}
return stringDate.toUpperCase();
}
This might need some optimisation, but it gives the idea.
来源:https://stackoverflow.com/questions/33389982/define-the-date-format-java-rd-st-th-nd