C Preprocessor concatenation with variable [duplicate]

问题

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Closed 6 years ago.

Possible Duplicate:
C preprocessor and concatenation

Is it possible to concatenate a C preprocessor with a variable name?

#define  WIDTH 32

int dataWIDTH;


// dataWIDTH should be interpreted as 'data32'

printf("%d",dataWIDTH);

回答1:

Your use case requires a double-unescaping; using the token pasting (##) operator by itself will just append the name of the preprocessor directive.

#define WIDTH 32

#define _MAKEDATA(n) data##n
#define MAKEDATA(n) _MAKEDATA(n)

int MAKEDATA(WIDTH) = 7;
int _MAKEDATA(WIDTH) = 8;

int main(int argc, char *argv[]) {
    printf("%d\n", data32);
    return 0;
}

yields

$ gcc -E foo.c 
int data32 = 7;
int dataWIDTH = 8;

int main(int argc, char *argv[]) {
    printf("%d\n", data32);
    return 0;
}

回答2:

There's a token pasting operator called ##, read about it for example here:

http://msdn.microsoft.com/en-us/library/09dwwt6y(v=vs.80).aspx

来源：https://stackoverflow.com/questions/13923425/c-preprocessor-concatenation-with-variable