How do I write dispatch_after GCD in Swift 3, 4, and 5?

问题

In Swift 2, I was able to use dispatch_after to delay an action using grand central dispatch:

var dispatchTime: dispatch_time_t = dispatch_time(DISPATCH_TIME_NOW, Int64(0.1 * Double(NSEC_PER_SEC))) 
dispatch_after(dispatchTime, dispatch_get_main_queue(), { 
    // your function here 
})

But this no longer seems to compile since Swift 3. What is the preferred way to write this in modern Swift?

回答1:

The syntax is simply:

// to run something in 0.1 seconds

DispatchQueue.main.asyncAfter(deadline: .now() + 0.1) {
    // your code here
}

Note, the above syntax of adding seconds as a Double seems to be a source of confusion (esp since we were accustomed to adding nsec). That "add seconds as Double" syntax works because deadline is a DispatchTime and, behind the scenes, there is a + operator that will take a Double and add that many seconds to the DispatchTime:

public func +(time: DispatchTime, seconds: Double) -> DispatchTime

But, if you really want to add an integer number of msec, μs, or nsec to the DispatchTime, you can also add a DispatchTimeInterval to a DispatchTime. That means you can do:

DispatchQueue.main.asyncAfter(deadline: .now() + .milliseconds(500)) {
    os_log("500 msec seconds later")
}

DispatchQueue.main.asyncAfter(deadline: .now() + .microseconds(1_000_000)) {
    os_log("1m μs seconds later")
}

DispatchQueue.main.asyncAfter(deadline: .now() + .nanoseconds(1_500_000_000)) {
    os_log("1.5b nsec seconds later")
}

These all seamlessly work because of this separate overload method for the + operator in the DispatchTime class.

public func +(time: DispatchTime, interval: DispatchTimeInterval) -> DispatchTime

It was asked how one goes about canceling a dispatched task. To do this, use DispatchWorkItem. For example, this starts a task that will fire in five seconds, or if the view controller is dismissed and deallocated, its deinit will cancel the task:

class ViewController: UIViewController {

    private var item: DispatchWorkItem?

    override func viewDidLoad() {
        super.viewDidLoad()

        item = DispatchWorkItem { [weak self] in
            self?.doSomething()
            self?.item = nil
        }

        DispatchQueue.main.asyncAfter(deadline: .now() + 5, execute: item!)
    }

    deinit {
        item?.cancel()
    }

    func doSomething() { ... }

}

Note the use of the [weak self] capture list in the DispatchWorkItem. This is essential to avoid a strong reference cycle. Also note that this does not do a preemptive cancelation, but rather just stops the task from starting if it hasn’t already. But if it has already started by the time it encounters the cancel() call, the block will finish its execution (unless you’re manually checking isCancelled inside the block).

回答2:

Swift 4:

DispatchQueue.main.asyncAfter(deadline: .now() + .milliseconds(100)) {
   // Code
}

For the time .seconds(Int), .microseconds(Int) and .nanoseconds(Int) may also be used.

回答3:

If you just want the delay function in

Swift 4 & 5

func delay(interval: TimeInterval, closure: @escaping () -> Void) {
     DispatchQueue.main.asyncAfter(deadline: .now() + interval) {
          closure()
     }
}

You can use it like:

delay(interval: 1) { 
    print("Hi!")
}

回答4:

after Swift 3 release, also the @escaping has to be added

func delay(_ delay: Double, closure: @escaping () -> ()) {
  DispatchQueue.main.asyncAfter(deadline: .now() + delay) {
    closure()
  }
}

回答5:

A somewhat different flavour of the Accepted Answer.

Swift 4

DispatchQueue.main.asyncAfter(deadline: .now() + 0.1 + .milliseconds(500) + 
.microseconds(500) + .nanoseconds(1000)) {
                print("Delayed by 0.1 second + 500 milliseconds + 500 microseconds + 
                      1000 nanoseconds)")
 }

回答6:

Swift 4

You can create a extension on DispatchQueue and add function delay which uses DispatchQueue asyncAfter function internally

extension DispatchQueue {
   static func delay(_ delay: DispatchTimeInterval, closure: @escaping () -> ()) {
      DispatchQueue.main.asyncAfter(deadline: .now() + delay, execute: closure)
   }
}

and use

DispatchQueue.delay(.milliseconds(10)) {
   print("task to be done")
}

回答7:

call DispatchQueue.main.after(when: DispatchTime, execute: () -> Void)

I'd highly recommend using the Xcode tools to convert to Swift 3 (Edit > Convert > To Current Swift Syntax). It caught this for me

回答8:

In Swift 4.1 and Xcode 9.4.1

Simple answer is...

//To call function after 5 seconds time
DispatchQueue.main.asyncAfter(deadline: .now() + 5.0) {
//Here call your function
}

回答9:

Swift 5 and above

DispatchQueue.main.asyncAfter(deadline: .now() + 2, execute: {
   // code to execute                 
})

回答10:

None of the answers mentioned running on a non-main thread, so adding my 2 cents.

On main queue (main thread)

let mainQueue = DispatchQueue.main
let deadline = DispatchTime.now() + .seconds(10)
mainQueue.asyncAfter(deadline: deadline) {
    // ...
}

DispatchQueue.main.asyncAfter(deadline: DispatchTime.now() + .seconds(10)) { 
    // ...
}

On global queue (non main thread, based on QOS specified) .

let backgroundQueue = DispatchQueue.global()
let deadline = DispatchTime.now() + .milliseconds(100)
backgroundQueue.asyncAfter(deadline: deadline, qos: .background) { 
    // ...
}

DispatchQueue.global().asyncAfter(deadline: DispatchTime.now() + .milliseconds(100), qos: .background) {
    // ...
}

回答11:

This worked for me in Swift 3

let time1 = 8.23
let time2 = 3.42

// Delay 2 seconds


DispatchQueue.main.asyncAfter(deadline: .now() + 2.0) {
    print("Sum of times: \(time1 + time2)")
}

回答12:

You can use

DispatchQueue.main.asyncAfter(deadline: .now() + .microseconds(100)) {
        // Code
    }

回答13:

try this

let when = DispatchTime.now() + 1.5
    DispatchQueue.main.asyncAfter(deadline: when) {
        //some code
    }

来源：https://stackoverflow.com/questions/37801436/how-do-i-write-dispatch-after-gcd-in-swift-3-4-and-5

标签

ios

swift

swift4

grand-central-dispatch

swift5