mongoDb $in with aggregate query

问题

How do I write an $in query along with aggregate in mongoDB? I want to write an equivalent mongoDB query for the SQL below

SELECT name,count(something) from collection1
where name in (<<list of Array>>) and cond1 = 'false'
group by name

回答1:

The equivalent mongo query follows:

db.collection1.aggregate([
    { "$match": { 
        "name": { "$in": arrayList },
        "cond1": "false"
    } }, 
    { "$group": {
        "_id": "$name",
        "count": { "$sum": "$something" }
    } }
])

来源：https://stackoverflow.com/questions/41034143/mongodb-in-with-aggregate-query