How do I convert the following String Date into Java Data format in Java?

问题

How do i convert the following String Date into Data format in Java?

"10/01/2012  06:45:23:245946"

I am using the following code

dateFormat = new SimpleDateFormat("MM/dd/yyyy  hh24:mm:ss:SSS");
java.util.Date parsedDate = dateFormat.parse("10/01/2012  06:45:23:245946");

And i am getting the following error

    java.text.ParseException: Unparseable date: "10/01/2012  06:45:23:245946"

回答1:

There is no hh24 in SimpleDateFormat, You should be using HH

回答2:

Your pattern is wrong. Try:

"MM/dd/yyyy  HH:mm:ss:SSS"

There is no hh24 in date matching pattern.

The pattern for hour is as follows:

H  Hour in day (0-23)  Number  0  
k  Hour in day (1-24)  Number  24

See the whole date pattern on SimpleDateFormat javadoc.

回答3:

You're almost there.

Get rid of the 24 after hh and change it to HH, that should make it work.

SimpleDateFormat dateFormat = new SimpleDateFormat("MM/dd/yyyy  HH:mm:ss:SSS");
Date parsedDate = dateFormat.parse("10/02/2012  06:45:23:245946");
System.out.println(parsedDate);

This will give you an error in time but parse the date successfull, as will all of our answers. This is fixed by trimming the milliseconds down to 3 digits from 245946 to 245

If you do however want to use 6 digits I would suggest looking into the JodaTime API for more advanced datehandling as JodaTime handles microseconds. But as for java.util.Date, you're out of luck I'm afraid.

Read this bugreport why: http://bugs.sun.com/bugdatabase/view_bug.do?bug_id=4148168

EDIT: Thanks Jesper for pointing out my bad wording

回答4:

The 24 in your date format is an invalid format specifier. Remove it. HH is the equivalent of hours on a 24-hour scale.

dateFormat = new SimpleDateFormat("MM/dd/yyyy  HH:mm:ss:SSS");

来源：https://stackoverflow.com/questions/13599865/how-do-i-convert-the-following-string-date-into-java-data-format-in-java

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java

simpledateformat