Box<T> to &T in Rust

问题

How do I call a function that expects a trait object if I have a Box<T> instead? In other words:

trait T { ... }

fn func(t: &T) { ... }

fn some_other_func() {
   b: Box<T>; // Provided

   // These work, but is there a better way?
   func( &*b );                // 1
   func( Borrow::borrow(&b) ); // 2
}

Both 1 and 2 seem wrong. Am I missing something obvious?

回答1:

&*foo is called a "reborrow", and is idiomatic.

来源：https://stackoverflow.com/questions/32084849/boxt-to-t-in-rust