System.out.print of string without 'ln'

旧街凉风 提交于 2019-12-12 11:39:46

问题


I have a byte array which looks like this:

[0, 0, 0, 0, 0, 0, 0, 0, 122, 98, 117, 54, 46, 0, 0, 115, 122, 42, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 116, 121, 116, 117, 108, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 32, 107, 111, 98, 105, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 122, 42, 109, 111, 119, 40, 0, 0, 0, 0, 0, 0, 107, 111, 98, 0, 0, 0, 0, 0, 98, 111, 40]

I wanted to print it as a string, so I wrote the following code:

System.out.println(new String(byteArray));

but there is no output. Next, I tried the following code:

for(byte b: byteArray){
 System.out.print((char) b);
}

but again there is no output. But when I tried the following code:

for(byte b: byteArray){
 System.out.println((char) b);
}

I was able to see the values.

My question is, why can't I create a string or why did the first printing of values from byteArray fail?


回答1:


try this

System.out.println(Arrays.toString(byteArray));



回答2:


Try this.

byte[] bytes = new byte[]{0, 0, 0, 0, 0, 0, 0, 0, 122, 98, 117, 54, 46, 0, 0, 115, 122, 42, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 116, 121, 116, 117, 108, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 32, 107, 111, 98, 105, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 122, 42, 109, 111, 119, 40, 0, 0, 0, 0, 0, 0, 107, 111, 98, 0, 0, 0, 0, 0, 98, 111, 40};
System.out.println(new String(bytes));



回答3:


Your byte array is mostly non printable characters, with a few random letters mixed in. But all you need is

String myString = new String(byteArray);

which will give you a valid string.

Try out the following code, as maybe it will better illustrate the issue your having.

 for (char c : new String(byteArray).toCharArray())
  {
     System.out.printf("Character: %s Hex: %02x \r",c,(int)c);
  }


来源:https://stackoverflow.com/questions/22494948/system-out-print-of-string-without-ln

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