Selecting all corresponding fields using MAX and GROUP BY

Question

I have this table :

And I would like to make a request that would return for each deal_id the row with the highest timestamp, and the corresponding status_id.

So for this example, I would have returned 2 rows :

1226, 3, 2009-08-18 12:10:25
1227, 2, 2009-08-17 14:31:25

I tried to do it with this query

SELECT deal_id, status_id, max(timestamp) FROM deal_status GROUP BY deal_id

but it would return the wrong status_id :

1226, 1, 2009-08-18 12:10:25
1227, 1, 2009-08-17 14:31:25

Answer 1

without a single primary key field, I think your best bet is:

select * from deal_status
inner join
  (select deal_id as did, max(timestamp) as ts
  from deal_status group by deal_id) as ds
  on deal_status.deal_id = ds.did and deal_status.timestamp = ds.ts

this still won't work if you allow having two different statuses for the same product at the same time

Answer 2

Hi i hope this gives what u want it

select deal_id,status_id, timestamp from deal_status 
inner join
  (select deal_id as did,max(timestamp) as ts
  from deal_status group by deal_id  )as ds
  on deal_status.deal_id = ds.did and deal_status.timestamp = ds.ts order by deal_id