Storing an integer into a char* in C++

问题

I'm writing some code that returns an integer, which then needs to be outputted using printw from the ncurses library. However, since printw only takes char*, I can't figure out how to output it.

Essentially, is there a way to store a integer into a char array, or output an integer using printw?

回答1:

printw() accepts const char * as a format specifier. What you want is

printw("%d",yournumber);

回答2:

The itoa function converts an int to char*.

回答3:

Use itoa() or sprintf() to convert integer to ascii string.

Example:

char s[50];
sprintf(s, "%d", someInteger);

now u can pass s as char*

回答4:

itoa will help you.

来源：https://stackoverflow.com/questions/1936913/storing-an-integer-into-a-char-in-c