sizeof('z') result unexpected [duplicate]

问题

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Closed 8 years ago.

Possible Duplicate:
Size of character ('a') in C/C++

Why does this program output 4 and not 1?

void main()
{
   printf("%d",int(sizeof('z')));
}

'z' is a character and sizeof('z') must print 1?

回答1:

'z' is a character literal and in C a character literal is of type int. So sizeof('z') equals sizeof(int) on your implementation.

回答2:

Sizeof char.

Perhaps surprisingly, character constants in C are of type int, so sizeof('a') is sizeof(int)

来源：https://stackoverflow.com/questions/6163776/sizeofz-result-unexpected