问题
I am using SecureRandom.urlsafe_base64(8) in order to create unique ids in my system that are URL safe.
I would like to know how to calculate the probability of collision? I am inserting about 10.000 of those ids into an array, and I want to avoid checking if one of the keys is already in the array, but I also want to make sure that are not repeated? What are the chances?
回答1:
There is a good approximation of this probability (which relates to the birthday problem). If there are k potential values and n are sampled, the probability of collision is:
k! / (k^n * (k - n)!)
The base64 method returns a base 64 string built from the inputted number of random bytes, not that number of random digits. Eight random bytes gives us k = 256^8, about 1.8446744e+19. You are generating 10,000 of these strings, so n = 10,000, which gives us a probability of 2.710498492319857e-12, which is very low.
回答2:
You do not make something sure by calculation a probability, you only know how likely it might happen.
To protect yourself just add a unique index to the database column. That ensures that you cannot store duplicates in your database. The insertion will raise an ActiveRecord::InvalidStatement error when this very unlikely (see @AndrewPilser's answer) event happens.
来源：https://stackoverflow.com/questions/24685501/probability-of-collision-of-securerandom-urlsafe-base648-in-ruby