问题
For an array, when I type:
puts array[0]
==> text
Yet when I type
puts array[0].to_s
==> ["text"]
Why the brackets and quotes? What am I missing?
ADDENDUM: my code looks like this
page = open(url) {|f| f.read }
page_array = page.scan(/regex/) #pulls partial urls into an array
partial_url = page_array[0].to_s
full_url = base_url + partial_url #adds each partial url to a consistent base_url
puts full_url
what I'm getting looks like:
http://www.stackoverflow/["questions"]
回答1:
This print the array as is without brackets
array.join(", ")
回答2:
to_s is just an alias to inspect for the Array class.
Not that this means a lot other than instead of expecting array.to_s to return a string it's actually returning array.inspect which, based on the name of the method, isn't really what you are looking for.
If you want just the "guts" try:
page_array.join
If there are multiple elements to the array:
page_array.join(" ")
This will make:
page_array = ["test","this","function"]
return:
"test this function"
What "to_s" on an Array returns, depends on the version of Ruby you are using as mentioned above. 1.9.X returns:
"[\"test\"]"
回答3:
You need to show us the regex to really fix this properly, but this will do it:
Replace this
partial_url = page_array[0].to_s
with this
partial_url = page_array[0][0]
回答4:
This doesn't necessarily fix why you are getting a doubled-up array, but you can flatten it and then call the first element like this.
page_array = page.scan(/regex/).flatten
Flattening takes out stacked arrays and creates one level, so if you had [1,2,[3,[4,5,6]]]
and called flatten on it, you would get [1,2,3,4,5,6]
It is also more robust than doing array[0][0]
, because, if you had more than two arrays nested in the first element, you would run into the same issue.
Iain is correct though, without seeing the regex, we can't suss out the root cause.
来源:https://stackoverflow.com/questions/8829600/why-does-array-to-s-return-brackets