问题
I have two variables : count, which is a number of my filtered objects, and constant value per_page. I want to divide count by per_page and get integer value but I no matter what I try - I'm getting 0 or 0.0 :
>>> count = friends.count()
>>> print count
1
>>> per_page = 2
>>> print per_page
2
>>> pages = math.ceil(count/per_pages)
>>> print pages
0.0
>>> pages = float(count/per_pages)
>>> print pages
0.0
What am I doing wrong, and why math.ceil gives float number instead of int ?
回答1:
Python does integer division when both operands are integers, meaning that 1 / 2 is basically "how many times does 2 go into 1", which is of course 0 times. To do what you want, convert one operand to a float: 1 / float(2) == 0.5, as you're expecting. And, of course, math.ceil(1 / float(2)) will yield 1, as you expect.
(I think this division behavior changes in Python 3.)
回答2:
Integer division is the default of the / operator in Python < 3.0. This has behaviour that seems a little weird. It returns the dividend without a remainder.
>>> 10 / 3
3
If you're running Python 2.6+, try:
from __future__ import division
>>> 10 / 3
3.3333333333333335
If you're running a lower version of Python than this, you will need to convert at least one of the numerator or denominator to a float:
>>> 10 / float(3)
3.3333333333333335
Also, math.ceil always returns a float...
>>> import math
>>> help(math.ceil)
ceil(...)
ceil(x)
Return the ceiling of x as a float.
This is the smallest integral value >= x.
回答3:
They're integers, so count/per_pages is zero before the functions ever get to do anything beyond that. I'm not a Python programmer really but I know that (count * 1.0) / pages will do what you want. There's probably a right way to do that however.
edit — yes see @mipadi's answer and float(x)
回答4:
its because how you have it set up is performing the operation and then converting it to a float try
count = friends.count()
print count
per_page = float(2)
print per_page
pages = math.ceil(count/per_pages)
print pages
pages = count/per_pages
By converting either count or per_page to a float all of its future operations should be able to do divisions and end up with non whole numbers
回答5:
>>> 10 / float(3)
3.3333333333333335
>>> #Or
>>> 10 / 3.0
3.3333333333333335
>>> #Python make any decimal number to float
>>> a = 3
>>> type(a)
<type 'int'>
>>> b = 3.0
>>> type(b)
<type 'float'>
>>>
The best solution maybe is to use from __future__ import division
回答6:
From Python documentation (math module):
math.ceil(x)Return the ceiling of x as a float, the smallest integer value greater than or equal to x.
来源：https://stackoverflow.com/questions/3367315/basic-python-arithmetic-division