Pretty-print a Map in Java

问题

I am looking for a nice way to pretty-print a Map.

map.toString() gives me: {key1=value1, key2=value2, key3=value3}

I want more freedom in my map entry values and am looking for something more like this: key1="value1", key2="value2", key3="value3"

I wrote this little piece of code:

StringBuilder sb = new StringBuilder();
Iterator<Entry<String, String>> iter = map.entrySet().iterator();
while (iter.hasNext()) {
    Entry<String, String> entry = iter.next();
    sb.append(entry.getKey());
    sb.append('=').append('"');
    sb.append(entry.getValue());
    sb.append('"');
    if (iter.hasNext()) {
        sb.append(',').append(' ');
    }
}
return sb.toString();

But I am sure there is a more elegant and concise way to do this.

回答1:

Or put your logic into a tidy little class.

public class PrettyPrintingMap<K, V> {
    private Map<K, V> map;

    public PrettyPrintingMap(Map<K, V> map) {
        this.map = map;
    }

    public String toString() {
        StringBuilder sb = new StringBuilder();
        Iterator<Entry<K, V>> iter = map.entrySet().iterator();
        while (iter.hasNext()) {
            Entry<K, V> entry = iter.next();
            sb.append(entry.getKey());
            sb.append('=').append('"');
            sb.append(entry.getValue());
            sb.append('"');
            if (iter.hasNext()) {
                sb.append(',').append(' ');
            }
        }
        return sb.toString();

    }
}

Usage:

Map<String, String> myMap = new HashMap<String, String>();

System.out.println(new PrettyPrintingMap<String, String>(myMap));

Note: You can also put that logic into a utility method.

回答2:

Arrays.toString(map.entrySet().toArray())

回答3:

Have a look at the Guava library:

Joiner.MapJoiner mapJoiner = Joiner.on(",").withKeyValueSeparator("=");
System.out.println(mapJoiner.join(map));

回答4:

Apache libraries to the rescue!

MapUtils.debugPrint(System.out, "myMap", map);

All you need Apache commons-collections library (project link)

Maven users can add the library using this dependency:

<dependency>
    <groupId>commons-collections</groupId>
    <artifactId>commons-collections</artifactId>
    <version>3.2.1</version>
</dependency>

回答5:

Simple and easy. Welcome to the JSON world. Using Google's Gson:

new Gson().toJson(map)

Example of map with 3 keys:

{"array":[null,"Some string"],"just string":"Yo","number":999}

回答6:

When I have org.json.JSONObject in the classpath, I do:

Map<String, Object> stats = ...;
System.out.println(new JSONObject(stats).toString(2));

(this beautifully indents lists, sets and maps which may be nested)

回答7:

Using Java 8 Streams:

Map<Object, Object> map = new HashMap<>();

String content = map.entrySet()
                    .stream()
                    .map(e -> e.getKey() + "=\"" + e.getValue() + "\"")
                    .collect(Collectors.joining(", "));

System.out.println(content);

回答8:

I prefer to convert the map to a JSON string it is:

a standard
human readable
supported in editors like Sublime, VS Code, with syntax highlighting, formatting and section hide/show
supports JPath so editors can report exactly which part of the object you have navigated to

supports nested complex types within the object

import com.fasterxml.jackson.core.JsonProcessingException;
import com.fasterxml.jackson.databind.ObjectMapper;

public static String getAsFormattedJsonString(Object object)
{
    ObjectMapper mapper = new ObjectMapper();
    try
    {
        return mapper.writerWithDefaultPrettyPrinter().writeValueAsString(object);
    }
    catch (JsonProcessingException e)
    {
        e.printStackTrace();
    }
    return "";
}

回答9:

Look at the code for HashMap#toString() and AbstractMap#toString() in the OpenJDK sources:

class java.util.HashMap.Entry<K,V> implements Map.Entry<K,V> {
       public final String toString() {
           return getKey() + "=" + getValue();
       }
   }
 class java.util.AbstractMap<K,V> {
     public String toString() {
         Iterator<Entry<K,V>> i = entrySet().iterator();
         if (! i.hasNext())
            return "{}";

        StringBuilder sb = new StringBuilder();
        sb.append('{');
        for (;;) {
            Entry<K,V> e = i.next();
            K key = e.getKey();
            V value = e.getValue();
            sb.append(key   == this ? "(this Map)" : key);
            sb.append('=');
            sb.append(value == this ? "(this Map)" : value);
            if (! i.hasNext())
                return sb.append('}').toString();
            sb.append(", ");
        }
    }
}

So if the guys from OpenJDK did not find a more elegant way to do this, there is none :-)

回答10:

You should be able to do what you want by doing:

System.out.println(map) for example

As long as ALL your objects in the map have overiden the toString method you would see:
{key1=value1, key2=value2} in a meaningfull manner

If this is for your code, then overiding toString is a good habit and I suggest you go for that instead.

For your example where your objects are Strings you should be fine without anything else.
I.e. System.out.println(map) would print exactly what you need without any extra code

回答11:

public void printMapV2 (Map <?, ?> map) {
    StringBuilder sb = new StringBuilder(128);
    sb.append("{");
    for (Map.Entry<?,?> entry : map.entrySet()) {
        if (sb.length()>1) {
            sb.append(", ");
        }
        sb.append(entry.getKey()).append("=").append(entry.getValue());
    }
    sb.append("}");
    System.out.println(sb);
}

回答12:

I guess something like this would be cleaner, and provide you with more flexibility with the output format (simply change template):

    String template = "%s=\"%s\",";
    StringBuilder sb = new StringBuilder();
    for (Entry e : map.entrySet()) {
        sb.append(String.format(template, e.getKey(), e.getValue()));
    }
    if (sb.length() > 0) {
        sb.deleteCharAt(sb.length() - 1); // Ugly way to remove the last comma
    }
    return sb.toString();

I know having to remove the last comma is ugly, but I think it's cleaner than alternatives like the one in this solution or manually using an iterator.

回答13:

As a quick and dirty solution leveraging existing infrastructure, you can wrap your uglyPrintedMap into a java.util.HashMap, then use toString().

uglyPrintedMap.toString(); // ugly
System.out.println( uglyPrintedMap ); // prints in an ugly manner

new HashMap<Object, Object>(jobDataMap).toString(); // pretty
System.out.println( new HashMap<Object, Object>(uglyPrintedMap) ); // prints in a pretty manner

回答14:

Does not answer exactly the question, but it is worth mentioning Lombodok @ToString annotation. If you annotate with @ToString the key / value classes, then doing System.out.println(map) will return something meaningful.

It also works very well with maps-of-maps, for example: Map<MyKeyClass, Map<String, MyValueClass>> will be printed as

{MyKeyClass(properties...)={string1=MyValuesClass(properties...), string2=MyValuesCalss(properties...),..}, ... }

回答15:

String result = objectMapper.writeValueAsString(map) - as simple as this!

Result:

{"2019-07-04T03:00":1,"2019-07-04T04:00":1,"2019-07-04T01:00":1,"2019-07-04T02:00":1,"2019-07-04T13:00":1,"2019-07-04T06:00":1 ...}

P.S. add Jackson JSON to your classpath.

来源：https://stackoverflow.com/questions/10120273/pretty-print-a-map-in-java

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