问题
I want a solution for udnerstanding how to hold a real loop counter as Java in xQuery, not a workaround for my particular simplified demo. I know in xQuery 3.0 there is a count reserved word for FLOWR structures but its useless pre-Saxon 9.something. Here my example.
for $elem at $x in /Data/* return element Elem {
attribute Name {concat('_',$x,'.',name($elem))},
(: ...10 lines of code... :)
for $subelem at $y in $elem/*
(: ...5 lets... :)
return element SubElemen {
attribute Name {concat('_',$x,'.',$y,'_',name($subelement))},
(...20 lines of other attrs and elements ...)
for $subsubelem at $z in $subElem/SubSubElement
let $absIterIndex := 'THIS IS WHAT IM LOOKING'
let $subSubElemName := concat('_',$absIterIndex,'_',name($subElem))
return
element SubSubElem {
attribute Name {$subsubelem},
(..100 lines more playing with $x, $y, $absIterIndex, all lets for that iteration, attributes depending on them...)
The output is something like this (real data hidden and simplified)
<Elem Name="_1.Name">
<SubElem Name="_1.1_Name">
<SubSubElem Name="_1.First"/>
<SubSubElem Name="_2.Second"/>
<SubSubElem Name="_3.Third"/>
</SubElem Name="_1.1_Name">
<SubElem Name="_1.2_Name">
<SubSubElem Name="_4.Fourth"/>
<SubSubElem Name="_5.Fifth"/>
<SubSubElem Name="_6.Sixth"/>
<SubSubElem Name="_7.Seventh"/>
</SubElem Name="_1.1_Name">
<Elem Name="_2.Name">
<SubElem Name="_2.1_Name">
<SubSubElem Name="_8.Eighth"/>
<SubSubElem Name="_9.Ninth"/>
<SubSubElem Name="_10.Tenth"/>
<SubSubElem Name="_11.Eleventh"/>
</SubElem Name="_2.1_Name">
<SubElem Name="_2.2_Name"/>
</Elem Name="_2.Name">
<Elem Name="_3.Name">
<SubElem Name="_3.1_Name">
<SubSubElem Name="_12.Twelven"/>
</SubElem Name="_3.1_Name">
<SubElem Name="_3.2_Name"/>
</Elem Name="_3.Name">
This is a extension of a previous question Autoincremental auxiliar index var for XQuery nested loops, which I accepted the solution for the xQuery 3.0 counter, and then propose an alternative for manually doing it. But know i think the perspective is different and more concrete, and with a new example. If you think it should be deleted just tell it to me.
回答1:
New question - new answer.
But the principle remains the same: produce an unnumbered result first, then apply the numbering. This may require rewriting the result.
Insert your code instead of the XML comment below.
declare function local:renumber($number, $string)
{
replace($string, 'THIS IS WHAT IM LOOKING', string($number))
};
declare function local:renumber($subSubElems, $number, $nodes)
{
for $node in $nodes
return
typeswitch ($node)
case attribute() return attribute {node-name($node)} {local:renumber($number, $node)}
case processing-instruction() return processing-instruction {name($node)} {local:renumber($number, $node)}
case comment() return comment {local:renumber($number, $node)}
case text() return text {local:renumber($number, $node)}
default (: element() :) return
element {node-name($node)}
{
local:renumber
(
$subSubElems,
if ($subSubElems[. is $node]) then count($subSubElems[. << $node]) + 1 else $number,
($node/@*, $node/node())
)
}
};
let $result := <result>{<!-- your code here -->}</result>
return local:renumber($result//SubSubElem, 0, $result/node())
回答2:
What you could do is add an extra pass over the result sequence of your nested iterations, i.e.
declare variable $script := 'abc defg h ijklm nop
qrs tu vw
xy z';
for $letter at $lettersTotal in
(
for $line at $numLine in tokenize($script, '(\r\n?|\n\r?)')
for $word at $numWord in tokenize(normalize-space($line),' ')
for $codepoint at $numLetter in string-to-codepoints($word)
return codepoints-to-string($codepoint)
)
return ($lettersTotal, $letter)
This returns
1 a 2 b 3 c 4 d 5 e 6 f 7 g 8 h 9 i 10 j 11 k 12 l 13 m 14 n 15 o 16 p 17 q 18 r 19 s 20 t 21 u 22 v 23 w 24 x 25 y 26 z
If you are lucky, your XQuery processor can stream the result without materializing the sequence.
来源:https://stackoverflow.com/questions/11311618/autoincremental-auxiliar-index-var-for-xquery-nested-loops-w-dynamical-count