How to get the XPath result without any commas or square brackets?

问题

I have a code such as:

<out:a>
<out:Name Type="First" TypeCode="Best">JAE</out:Name>
<out:Name Type="Last" TypeCode="Best">ADAMS</out:Name>
</out:a>

When I gave the XPath expression as

(//*[local-name() = 'Name']/text())[1],(//*[local-name() = 'Name']/text())[2],

I got the result as [JAE,ADAMS]

How can I give the XPath expression so that I can the result as JAE ADAMS?

回答1:

Your question is unclear as to where you are using this XPath expression.

In most cases you could use something like:

concat(//*:Name[@Type='First'], " ", //*:Name[@Type='Last'])

In SoapUI XPath assertion, the concatenation is performed automatically, so just a simple:

${#Response#//*:Name[@Type='First']} ${#Response#//*:Name[@Type='Last'])}

(note the extra space) will work.

回答2:

Possibly string-join will do. Try:

string-join( ((//*[local-name() = 'Name']/text())[1],(//*[local-name() = 'Name']/text())[2]), ' ' )

string-join( (//*[local-name() = 'Name']/text())[position() le 2], ' ' )

string-join( subsequence( //*[local-name() = 'Name']/text(), 1, 2), ' ')

回答3:

The commas and square brackets are a notation that indicates that the result is a node set or sequence. You apparently would prefer a string.

First, however, note that your XML is not well-formed; it uses an undeclared namespace prefix. Here is your XML fixed to be well-formed:

<out:a xmlns:out="example.com/out">
  <out:Name Type="First" TypeCode="Best">JAE</out:Name>
  <out:Name Type="Last" TypeCode="Best">ADAMS</out:Name>
</out:a>

Then, any of these XPath expressions

XPath 1.0
```
concat(/*/*[1], ' ', /*/*[2])
```

XPath 1.0 (namespace-responsible)

concat(//out:Name[1], ' ', //out:Name[2])

XPath 2.0
```
string-join(/*/*, ' ')
```
XPath 2.0
```
string-join(normalize-space(), ' ')
```

Will yield the string

JAE ADAMS

you request.

来源：https://stackoverflow.com/questions/34754733/how-to-get-the-xpath-result-without-any-commas-or-square-brackets

标签

xml

xpath

soapui