问题
e.g. I want to delete the latest three records in below table
root@localhost:[test]10:14:02>select * from delete_test order by create_time desc;
+----+------+---------------------+
| id | code | create_time |
+----+------+---------------------+
| 9 | fff | 2016-06-18 10:08:28 |
| 8 | eee | 2016-06-18 10:08:21 |
| 7 | ddd | 2016-06-18 10:08:15 |
| 3 | ccc | 2016-06-17 22:18:48 |
| 2 | bbb | 2016-06-17 22:18:42 |
| 1 | aaa | 2016-06-17 22:18:37 |
+----+------+---------------------+
first I tried
root@localhost:[test]10:14:14>delete from delete_test where code in (select code from delete_test order by create_time desc limit 3);
ERROR 1235 (42000): This version of MySQL doesn't yet support 'LIMIT & IN/ALL/ANY/SOME subquery'
then I tried
root@localhost:[test]10:17:05>delete a from delete_test a, (select code from delete_test order by create_time desc limit 3) b where a.code = b.code;
ERROR 1175 (HY000): You are using safe update mode and you tried to update a table without a WHERE that uses a KEY column
but code
filed is unique key
.
then I tried
root@localhost:[test]10:18:49>delete a from delete_test a join (select code from delete_test order by create_time desc limit 3) b on a.code = b.code where a.id>0;
ERROR 1175 (HY000): You are using safe update mode and you tried to update a table without a WHERE that uses a KEY column
but I used primary key
explicitly.
So I want to know how to delete the latest some records in --safe-updates
mode?
回答1:
You can do as simple as:
delete from delete_test order by create_time limit 3;
See it working here: http://sqlfiddle.com/#!9/04f68/1
If I didn't put in the right order just change the order by
part to order by create_time desc
来源:https://stackoverflow.com/questions/37892657/how-to-delete-the-latest-some-records-in-safe-updates-mode