问题
if a particular character is found at certain position, I need to replace it with a number and make entire string as negative decimal number . for ex:
if } is found at 14th position it need to be replaced with 2 and make it negative decimal number:
sed -e 's/^\(.\{9\}\)}/.\12/;s/\(.\)/-\1/' <<< '123 00}000150}'
output is:
-.123 00}0001502
But, expected output is:
123 -00}00015.02
回答1:
This will work:
sed -e 's/\(.* \)\(.\{8\}\)\(.*\)}/\1-\2.\32/' <<< '123 00}000150}'
\1 will have value: 123 ( Matches from first character till first space)
\2 : 00}00015 ( Next 8 characters)
\3 : 0 ( Characters until next } is found)
来源：https://stackoverflow.com/questions/36790322/how-to-convert-the-string-to-negative-decimal-number-in-ksh-unix