Delete where both columns match

问题

I have two tables

Person (contain oldest date (farthest in future) when person moved OR WILL moved to another address)

ID                OLDESTADDRESSMOVEDATE

1                     20161117
2                     20171211
3                     20160101


Address           

PersonID             AddressMOVETODATE
 1                       20161117
 1                       20161111
 1                       20141018
 2                       20171211
 2                       20151210

Now I want to write a DELETE query which will DELETE FROM ADDRESS THE ROWS for EACH person in PERSON, where AddressMOVETODATE is PREVIOUS THAN the one in OLDESTADDRESSMOVEDATE colum

e.g.

If I run that query the remaining rows in ADDRESS table should be

PersonID             AddressMOVETODATE
1                       20161117
2                       20171211

I have tried

DELETE FROM ADDRESS WHERE PERSONID = PERSON.ID and AddressMOVETODATE < Person.OLDESTADDRESSMOVEDATE

but it is not working. Also, how we will make sure we enter only CORRESPONDING columns of Person table e.g. we do not want to mess up by putting

Person ID = 1 and Person.OLDESTADDRESSMOVEDATE = 20171211 (of Person 2)

Please help.

Thanks,

Aiden

回答1:

You can query using row_number, cte and delete

;WITH cte AS
(
    SELECT *, RowN = ROW_NUMBER() OVER (PARTITION BY ID ORDER BY AddressMoveDate DESC) FROM Address
)
DELETE FROM cte WHERE RowN > 1

来源：https://stackoverflow.com/questions/40568218/delete-where-both-columns-match