In C++, is a constructor with only default arguments a default constructor?

问题

In the following code:

struct Foo
{
    Foo(int x=0);
};

Does the constructor count as a default constructor?

回答1:

C++98 §12.1/5 (emphasis mine):

A default constructor for a class X is a constructor of X that can be called without an argument. If there is no user-declared constructor for class X, a default constructor is implicitly declared.

So yes, it does count as a default constructor. See also.

来源：https://stackoverflow.com/questions/11250690/in-c-is-a-constructor-with-only-default-arguments-a-default-constructor