How to configure Django views and urls to render specific templates

问题

When I bring up 127.0.0.1:8000, the current page that show up is something.html template.

I would need to make it appear index.html at first launch, then when I click on other parts,it should go to 127.0.0.1:8000/something.html (or 127.0.0.1:8000/myapp/something.html).

What would be the structure to achieve this?
I frequently get error message : The current URL didn't match any of these.

Currently, my structure is

project
     ---myapp
          ---admin.py
          ---models.py
          ---url.py
          ---views.py
     ---static
     ---templates
          ---myapp
             ---html files
     ---mysite
          ---settings.py
          --- url.py

under my settings.py

STATIC_URL = '/static/'
STATIC_ROOT = os.path.join(BASE_DIR, 'static')

under mysettings/url.py

   urlpatterns = [
        # Examples:
        url(r'^$', 'mysite.views.home', name='home'),
        url(r'^myapp/', include('myapp.urls')),
        url(r'^admin/', include(admin.site.urls)),
    ]

mysite/urls.py

from django.conf.urls import include, url
from django.contrib import admin
from django.conf.urls import patterns
from django.views.generic import TemplateView


urlpatterns = [
    # Examples:
    url(r'^', include('myapp.urls')),
    url(r'^admin/', include(admin.site.urls)),
]


admin.site.site_header = 'Admin'

myapp/url.py

from . import views
from django.conf.urls import patterns, include, url
from django.views.generic import TemplateView


urlpatterns = patterns('',
    #brings up something.html when we comment it out. No module found if included.
    #url(r'^$', views.home, name='home'),
    url(r'^$', views.post_list, name='post_list'),
)

回答1:

Include urls of your myapp app in mysite/urls.py

from django.conf.urls import include, url
from django.contrib import admin
from django.conf import settings

urlpatterns = [
    url(r'^', include('myapp.urls')),
    url(r'^admin/', include(admin.site.urls)),

]

Now, all urls, starting by 127.0.0.1:8000, will check if there is a view that can handle the request. I recommend you to read this to understand how Django URL dispatcher works : [Django documentation - URL Dispatcher] (https://docs.djangoproject.com/en/1.8/topics/http/urls/). 2. Add new route in your myapp.urls:

from django.conf.urls import url, patterns
from . import views

urlpatterns = patterns('',
    url(r'^$', views.home, name='home'),
    url(r'^something$', views.something, name='something'),
    url(r'^posts$', views.post_list, name='post_list'),
)

Now :
127.0.0.1:8000/ will executed code of views.home
127.0.0.1:8000/something will executed code of views.something
127.0.0.1:8000/posts will executed code of views.post_list
Let's define these view now

3: Define the views in myapp.views :

from django.shortcuts import render

def home(request):
    """
    Return home page
    """
    return render(request, 'myapp/home.html')

def something(request):
    """
    Return something page
    """
    return render(request, 'myapp/something.html')

def post_list(request):
    """
    Return something page
    """
    # do what you want

Add your templates in myapp/templates/myapp/. Add home.html and something.html.

Now forget, the `.html

回答2:

You create a url (with attached view to it).
In the view you render any html page you want.

If you use function based views your 'mysite.views.home' may look like:

def home(request):
    ...
    return render(request, 'path/to/index.html')

and so on.

It's the basics so I won't talk about this much. You can find a good tutorial about mapping urls to views there.

来源：https://stackoverflow.com/questions/33765886/how-to-configure-django-views-and-urls-to-render-specific-templates

标签

python

django

django-templates

django-views