lua: iterate through all pairs in table

▼魔方 西西 提交于 2019-11-27 03:49:14

问题


I have a sparse lua table and I need to iterate over it. The Problem is, it seems that lua begins the iteration at 1, and terminates as soon as it finds a nil value. Here's and example:

> tab={}
> tab[2]='b'
> tab[5]='e'
> for i,v in ipairs(tab) do print(i,v) end
>               --nothing is output here
> tab[1]='a'
> for i,v in ipairs(tab) do print(i,v) end
1   a
2   b
>               --terminates after 2 (first nil value is tab[3])

Is there any way to get the desired output:

1   a
2   b
5   e

回答1:


You must use pairs instead of ipairs.

tab={}

tab[1]='a'
tab[2]='b'
tab[5]='e'

for k, v in pairs(tab) do print(k, v) end

Will output (in any order):

1   a
2   b
5   e

ipairs iterates over sequential integer keys, starting at 1 and breaking on the first nil pair.

pairs iterates over all key-value pairs in the table. Note that this is not guaranteed to iterate in a specific order.



来源:https://stackoverflow.com/questions/12584258/lua-iterate-through-all-pairs-in-table

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