问题
I wrote the following Test.ps1
PowerShell script to display a WPF GUI:
function LoadXamlFile( $path )
{
[System.Xml.XmlDocument]$xml = Get-Content -Path $path
$xmlReader = New-Object -TypeName System.Xml.XmlNodeReader -ArgumentList $xml
$xaml = [System.Windows.Markup.XamlReader]::Load( $xmlReader )
return $xaml
}
# Main Window
$MainWindow = LoadXamlFile 'MainWindow.xaml'
# Page 1
$Page1 = LoadXamlFile 'Page1.xaml'
$MainWindow.Content = $Page1
$TextBox1 = $MainWindow.FindName('TextBox1')
# The following line fails because $TextBox1 is null
$TextBox1.Text = 'test'
$MainWindow.ShowDialog()
This script requires the two following XAML files:
MainWindow.xaml
<Window
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
x:Name="MainWindow"
Title="WPF Test" Height="200" Width="400">
</Window>
Page1.xaml
<UserControl
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
x:Name="Page1">
<Grid>
<TextBox x:Name="TextBox1" HorizontalAlignment="Center" Height="23" Margin="0,-40,0,0" TextWrapping="Wrap" VerticalAlignment="Center" Width="120"/>
<Button x:Name="Button1" Content="Next" HorizontalAlignment="Center" Margin="0,40,0,0" VerticalAlignment="Center" Width="76"/>
</Grid>
</UserControl>
The issue, as stated in my PowerShell code, is that I can't access UserControl elements/properties after adding the UserControl to the main window.
I know I can access it with $Page1.FindName('TextBox1')
but is there a way to do it from the $MainWindow
object?
回答1:
You have to do a FindName
in the Content
of $MainWindow
$TextBox1 = $MainWindow.Content.FindName("TextBox1")
来源:https://stackoverflow.com/questions/28900141/access-usercontrol-elements-properties-from-main-window-in-a-wpf-xaml-powershell