问题
I have an input column (symbols) which has more than 10000 rows and they contain operator symbols and text values like ("",">","<","","****","inv","MOD","seen") as shown below in the code as values. This column doesn't contain any numbers. It only contains the value which are stated in the code.
What I would like to do is map those operator symbols ('<','>' etc) to different codes, 1) Operator_codes 2) Value_codes and have these two different codes as separate columns
I already have a working code but it is not very efficient as you can see I repeat the same operation twice. Once for Operator_codes and then for value_codes. I am sure there must be some efficient way to write this. I am new to R and not very familiar with other approach.
oper_val_concepts = function(DF){
operators_source = str_extract(.$symbols)
operators_source = as.data.frame(operators_source)
colnames(operators_source) <- c("Symbol")
operator_list = c("",">","<","-","****","inv","MOD","seen")
operator_codes = c(123L,14L,16L,13L,0L,0L,0L,0L)
value_codes=c(14L,12L,32L,123L,16L
,41L,116L,186L)
operator_code_map = map2(operator_list,operator_codes,function(x,y)c(x,y))
%>%
data.frame()
value_code_map = map2(operator_list,value_codes,function(x,y) c(x,y)) %>%
data.frame()
operator_code_map = t(operator_code_map)
value_code_map = t(value_code_map)
colnames(operator_code_map) <- c("Symbol","Code")
colnames(value_code_map) <- c("Symbol","Code")
rownames(operator_code_map) = NULL
rownames(value_code_map) = NULL
dfm<-merge(x=operators_source,y=operator_code_map,by="Symbol",all.x =
TRUE)
dfm1<-merge(x=operators_source,y=value_code_map,by="Symbol",all.x = TRUE)
}
t1 = oper_val_concepts(test)
dput command output is
structure(list(Symbols = structure(c(2L, 3L, 1L, 4L, 2L, 3L,
5L, 4L, 6L), .Label = c("****", "<", ">", "inv", "mod", "seen"
), class = "factor")), .Names = "Symbols", row.names = c(NA,-9L), class =
"data.frame")
I am expecting an output to be two columns in a dataframe as shown below.
回答1:
Based on what I am understanding, it seems like you want to create a dataframe that will act as a key (see key
below). Once you have this, you can just join the dataframe that just contains symbols with this key
dataframe.
df <- structure(list(Symbols = structure(c(2L, 3L, 1L, 4L, 2L, 3L,
5L, 4L, 6L), .Label = c("****", "<", ">", "inv", "mod", "seen"
), class = "factor")), .Names = "Symbols", row.names = c(NA, -9L), class = "data.frame")
key <- data.frame(Symbols = c("",">","<","-","****","inv","mod","seen"),
Oerator_code_map = c(123L,14L,16L,13L,0L,0L,0L,0L),
value_code_map = c(14L,12L,32L,123L,16L,41L,116L,186L))
df %>% left_join(key, by = "Symbols")
output
Symbols Oerator_code_map value_code_map
1 < 16 32
2 > 14 12
3 **** 0 16
4 inv 0 41
5 < 16 32
6 > 14 12
7 mod 0 116
8 inv 0 41
9 seen 0 186
来源:https://stackoverflow.com/questions/55473181/elegant-way-to-write-function