问题
i have column having multiple value like A0045 ,A00065 . i want to convert it 9945, 9965. Need to remove all 0 and character value and add 99 before that value.. replace(val,"A","99") will replace only A I want to go for A-Z occurrence.. Any char should be convert .. Please help
回答1:
How about
newValue = "99" + LEFT-TRIM( oldValue, "ABCDEFGHIJKLMNOPQRSTUVWXYZ0" ).
This should take all leading alpha and zero characters from the string, and prefix with 99.
回答2:
/************Try this*********************/
define variable word as character no-undo.
define variable i as integer no-undo.
assign word = "A00065".
/******to remove all the zeroes**************/
word = replace(word,substring(word,index(word,"0"),(r-index(word,"0") - 1)),"").
do i = 65 to 90:
if substring(word,1,1) = chr(i) then
do:
word = replace(word,substring(word,1,1),"99").
leave.
end.
end.
display word.
来源：https://stackoverflow.com/questions/46929456/how-to-convert-a0058-value-to-9958-in-progress-4gl